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Sauron [17]
3 years ago
15

Mrs. Averitt pipes an average of 62 words per minute how many words does it take her to type 3596 words

Mathematics
2 answers:
Schach [20]3 years ago
7 0

Answer:

58 minutes

Step-by-step explanation:

66=1

3596=?

66×1=66

3596÷66=58

?=58

AlexFokin [52]3 years ago
3 0

Answer:

58

Step-by-step explanation:

Divide 3596/63

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Solve the system of equations. 3x – 4y = 8 18x – 5y = 10 x= y =<br>​
Zepler [3.9K]

Answer:

Step-by-step explanation:

Solution by substitution method

3x-4y=8

and 18x-5y=10

Suppose,

3x-4y=8→(1)

and 18x-5y=10→(2)

Taking equation (1), we have

3x-4y=8

⇒3x=4y+8

⇒x=( 4y+8)/ 3  →(3)

Putting x= (4y+8 )/3  in equation (2), we get

18x-5y=10

18( (4y+8) /3)  -5y=10

⇒24y+48-5y=10

⇒19y+48=10

⇒19y=10-48

⇒19y= -38

⇒y=- 38 /19

 ⇒y= -2→(4)

Now, Putting y=-2 in equation (3), we get

x=4y+8

x= (4(-2)+8) /3

 ⇒x= (-8+8)/ 3

 ⇒x= 0/ 3

 

⇒x=0

∴x=0  and  y= -2

5 0
3 years ago
The two figures shown are congruent. which statement is true?
Masteriza [31]

Answer:

1st Option

Step-by-step explanation:

Hope it helps

4 0
3 years ago
Read 2 more answers
Find the difference. express your answer in simplest form. (2s/s^2-4s+4) - (4/s^2-4s+4)
LUCKY_DIMON [66]
To find the difference, we are going to destroy the parenthesis first, and then, we are going to perform the operations. Remember that to destroy a parenthesis preceded by a negative sign (-), you should change the signs of the factors inside the parenthesis:
\frac{2s}{s^2-4s+4} -( \frac{4}{s^2-4s+4} )
\frac{2s}{s^2-4s+4} -\frac{4}{s^2-4s+4}= \frac{2s-4}{s^2-4s+4}

Now we can factor both numerator and denominator and simplify:
\frac{2s-4}{s^2-4s+4} = \frac{2(s-2)}{(s-2)^2} = \frac{2}{s-2}

We can conclude that the difference in simplest form is: \frac{2}{s-2}
5 0
3 years ago
Read 2 more answers
If the sum of two consecutive odd numbers is 28 . find the numbers.​
Sauron [17]

Answer:

13 and 15

Step-by-step explanation:

13 and 15 are consecutive odd numbers and

13 + 15 = 28

7 0
3 years ago
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saveliy_v [14]

Answer:

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