The two shorter sides of triangle are 9 and 12. what is a possible length to make length of the third side to make the triangle acute with acuteT
F(X) = (3x + 5)/X
F(a + 2) = (3(a + 2) + 5)/(a + 2)
F(a + 2) = (3a + 6 + 5)/(a+2)
F(a + 2) = (3a + 11)/(a + 2).
This would be the final solution.
Answer:
(a) 0
(b) f(x) = g(x)
(c) See below.
Step-by-step explanation:
Given rational function:

<u>Part (a)</u>
Factor the <u>numerator</u> and <u>denominator</u> of the given rational function:

Substitute x = -1 to find the limit:

Therefore:

<u>Part (b)</u>
From part (a), we can see that the simplified function f(x) is the same as the given function g(x). Therefore, f(x) = g(x).
<u>Part (c)</u>
As x = 1 is approached from the right side of 1, the numerator of the function is positive and approaches 2 whilst the denominator of the function is positive and gets smaller and smaller (approaching zero). Therefore, the quotient approaches infinity.

7,030.3 I think... the way you typed it was kinda confusing though, 3 tenths? as in .3? if so, this is your answer