The answer is 7/10. Do you need help with any other problems?
Answer:
The answer to your question is below
Step-by-step explanation:
4.-
4a. 72
_<u>x 9</u>
638
4b. The error this student is doing is that he multiplies the first number but he must add the decenes of this result to the result of the multiplication of the second number and he is not doing that.
4c.- I told him the correct way to solve multiplications.
a) Multiply the first number and only write the units.
b) If the are decenes add then to the units of the result of the multiplication of the second number.
Example
72 9 x 2 = 18
<u>x9 </u> Just write the 8
8
72
<u>x 9</u>
648 9 x 7 = 63 + 1 from the previous operation
= 64
The correct answer here would be D. -1(3x+1)(x+5). You can find this answer by redistributing the problem.
-1(3x+1)(x+5)
-1(3x²+15x+1x+5)
-1(3x²+16x+5)
-3x²-16x-5
Using the math above, we can see that when we redistribute we get the original equation. That makes Choice D correct.
<span>2 dimensional and infinitely large hope it helped</span>
First look at all of the factors of 16:
(1, 16) (Cannot have only one group so this one does not work)
(2, 8) (this one is two equal groups of eight because 2x8 is 16)
(4, 4) (this one is four equal groups of four because 4x4 is 16)
(8, 2) (this one is eight equal groups of two because 8x2 is 16)
You can put it into two equal groups of 8 because 16/2 is 8
You can put it into four equal groups of 4 because 16/4 is 4
You can put it into eight equal groups of 2 because 16/8 is 2
I hope this helps!
