As the new mathematical operation is defined by a△b=a^2-b/b-a^2, the value of 4△3 using the same operation will be 4△3 = -1
As per the question statement, we are given a new mathematical operation a△b=a^2-b/b-a^2 and we are supposed to find the value of 4△3 using the same operation.
Given, a△b=a^2-b/b-a^2
now 4△3 = (4^2-3) / (3-4^2)
4△3 = (16-3) / (3-16)
4△3 = 13 / -13
4△3 = -1
Hence, as the new mathematical operation is defined by a△b=a^2-b/b-a^2, the value of 4△3 using the same operation will be 4△3 = -1.
- Mathematical operation: An operator in mathematics is often a mapping or function that transforms components of one space into elements of another.
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You would distibute first distribute
6x-10=8
add 10 on both sides
6x=18
Then you divide 6 on both sides to get x by itself so
x=3
9 * 3/4 = 6.75
You could change 3/4 into a decimal by dividing 3 by 4, which equals ,75.
60 = (10 + 20 + 30 + 40 + x)/5
300 = 100 + x
x = 200
Answer: 200
