Question

Write 1-2log7x as a single logarithm

Answer 1

Answer:

$log_{7} \frac{7}{x^{2} }$

Step-by-step explanation:

We need to write $1 - 2log_{7}x$ as a single logarithm.

We know that

$log_{7}7 = 1$

Therefore we have:

$log_{7}7 - 2log_{7}x$

→ $log_{7}7 - log_{7}x^{2}$

→ $log_{7} \frac{7}{x^{2} }$

The solution is: $log_{7} \frac{7}{x^{2} }$