3 years ago

Is 6200 ft greater less than 1 mile 900 ft

Mathematics

1 answer:

aliina [53]3 years ago

5 0

The answer is 1 mile 900 feet.

You might be interested in

Rita wrote an inequality for each statement. Select all statements whose inequality is an incorrect representation of the statem

solmaris [256]

The medical students m>12,the temperature of students s=>25, and the ideal candidate c=<5

8 0

3 years ago

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down; drag it into the corre

Alex777 [14]

8x^3 -5x^2 + 8x + 9+5x^3 + 3x^2 - 5x + 4 =
8x^3+5x^3-5x^2 + 3x^2+ 8x - 5x+ 9<span>+ 4 = </span>
13x^3-2x^2+3x+13

3 0

3 years ago

Que costaría más comprar una vaca o comprar hamburguesas de 1€ hasta igualar a una vaca.

butalik [34]

Answer:

haha pues cuesta mas las hamburgesas porque toca ir al doctor despues

Step-by-step explanation:

8 0

2 years ago

For what value of k will the relation y = kx² + 8x + 8 have only one zero? (3 marks)

Lana71 [14]

Answer:

Step-by-step explanation:

2x^2 + 8x + 8

factor the 2 out : 2(x^2 + 4x + 4)

2(x + 2)^2

x = -2

4 0

2 years ago

The extensions of the legs AB and CD of a trapezoid ABCD intersect at point E. Find the lengths of the sides of △AED if AB=5cm,

Lynna [10]

Answer:

AE = 15 cm; ED = 18 cm; AD = 15 cm (given)

Step-by-step explanation:

ΔBEC ~ ΔAED so ...

AD/BC = AE/BE = (BE+AB)/BE = 1 + AB/BE

Substituting given numbers (lengths in centimeters), we have ...

15/10 = 1 + 5/BE

1/2 = 5/BE

BE = 10

Similarly, ...

1/2 = 6/CE

CE = 12

Then the unknown sides are ...

AE = AB + BE = 5 + 10 = 15 . . . cm

ED = CE + CD = 12 + 6 = 18 . . . cm

8 0

3 years ago