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ololo11 [35]
3 years ago
15

Leila runs 4 miles in 30 minutes. At the same rate, how many minutes would she take to run 10 miles?

Mathematics
2 answers:
omeli [17]3 years ago
6 0
\bf \begin{array}{ccllll}
miles&minutes\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
4&30\\
10&x
\end{array}\implies \cfrac{4}{10}=\cfrac{30}{x}

solve for "x"
Marizza181 [45]3 years ago
3 0
30/4=7.5. 7.5 minutes every mile... That means that she ran 75 minutes
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Write an equation in the form y = mx + b for the line that has a slope of ¼ and contains the point (12, 3).
Alborosie
\bf \begin{array}{ccccccccc}
&&x_1&&y_1\\
%  (a,b)
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Read 2 more answers
Lily and Elsa are both college students.Before mom gave them this months allowance lily had $750 and Elsa had &215.After mom
Drupady [299]

After mom gave each girl an equal amount of money for this months allowance, lily had twice as much money as Elsa. Thus mom gave $ 320 to each girl

<em><u>Solution:</u></em>

Given that Lily and Elsa are both college students

Before mom gave them this months allowance lily had $750 and Elsa had &215

<em><u>Amount (in dollars) with Lily and Elsa already is given as:</u></em>

amount with Lily = $ 750

amount with Elsa = $ 215

After mom gave each girl an equal amount of money for this months allowance, lily had twice as much money as Elsa

Let "x" be the equal amount of money which mom gave to Lily and Elsa

Now amount with Lily and Elsa after mom gave equal amount is:

amount with Lily = amount with Lily already + x

amount with Lily = 750 + x

amount with Elsa = amount with Elsa already + x

amount with Elsa = 215 + x

Given that lily had twice as much money as Elsa

Amount with lily = 2(amount with elsa)

750 + x = 2(215 + x)

750 + x = 430 + 2ax

2x - x = 750 - 430

x = 320

Therefore mom gave $ 320 to each girl

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