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Illusion [34]
4 years ago
9

Jonathan has been on a diet since January 2013. So far, he has been losing weight at a steady rate. Bases on monthly weigh-ins,

his weight, w, can be modeled by the function w=-3m+205 where m is the number of months after January 2013.
a) How much did Jonathan weight at the start of the diet?

b) How much weight has Jonathan been losing each month?

c) How many months did it take Jonathan to lose 45 pounds?
Mathematics
1 answer:
Ivan4 years ago
7 0
a)\ \ \ w(m)=-3m+205\\\\m=0\ \ \ - at\ the\ start\ of\ the\ diet\\ \\w(0)=-3\cdot0+205=205\\ \\Ans.\ weigh\ at\ the\ start\ of\ the\ diet\ is\ 205\ pounds\\ \\b)\ \ \ w(m+1)=-3(m+1)+2015=-3m-3+205=-3m+202\\ \\w(m+1)-w(m)=-3m+202-(-3m+205)=\\ \\=-3m+202+3m-205=-3\\ \\Ans.\ Jonathan\ has\ each\ month\ 3\ been\ losing \\ \\ w(m)=205-45=160\ \ \ \Rightarrow\ \ \ -3m+205=160\ \ \ \Rightarrow\ \ \-3m=-45\\ \\m=15\\ \\Ans.\ 15\ month
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Vilka [71]

Answer:

Each person will be getting 2\frac{2}{5} pieces  of licorice

Step-by-step explanation:

If we have 12 pieces of licorice

To divide it equally among 5 people following formula will be used

Pieces to be given to each person = \frac{total\, pieces}{total\,people}

                                                           = =\frac{12}{5} \\2.4\\

So

Each person will be getting 2\frac{2}{5} pieces  of licorice

Keywords: Algebra

Learn more about algebra at:

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4 0
4 years ago
36 is 120% of what number
nadezda [96]
Let, the number = x
Then,x * 120% = 36
x * 1.20 = 36   [ 120% = 1.20 ]
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In short, Your Answer would be 30

Hope this helps!
6 0
3 years ago
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Evaluate Cot0 if sin0= square root of 6/5
Lina20 [59]
To evaluate cot θ given that sinθ=√6/5 we shall have:
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6 0
3 years ago
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Andrej [43]

Answer:

a) Josef jogging from A to B;

i. speed = 2 m/s

ii. velocity = 2m/s

a) a) Josef jogging from A to C;

speed = 1.9 m/s

ii. velocity = 2.2 m/s

Step-by-step explanation:

One major difference between speed and velocity is that speed is a scalar quantity, while velocity is a vector quantity.

a) Josef jogging from A to B;

distance = 300 m

time = 2.5 seconds = 150 seconds

i. his average speed = \frac{distance}{time}

                               = \frac{300}{150}

                               = 2 m/s

ii. his average velocity = \frac{displacement}{time}

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b) Josef jogging from A to C,

distance = 300 + 100 = 400 m

time = 2.5 + 1 = 3.5 minutes

        = 210 seconds

i. his average speed = \frac{distance}{time}

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ii. his average velocity = \frac{\sqrt{V_{1} ^{2}   + V_{2} ^{2} } }{2}

V_{1} ^{2} = 4 m/s

V_{2} ^{2} = 1.9 m/s

his average velocity = \frac{\sqrt{4^{2} + 1.9^{2}  } }{2}

                                  = 2.2 m/s

5 0
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Marat540 [252]
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