<img src="https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20%20%5Cleft%20%5C%7B%20%7B%7By%3D2%7D%20%5Catop%20%7Bx%3D2%7D%7D%20%5Cright.%2

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3 years ago

0" id="TexFormula1" title=" x^{2} \left \{ {{y=2} \atop {x=2}} \right. " alt=" x^{2} \left \{ {{y=2} \atop {x=2}} \right. " align="absmiddle" class="latex-formula">

Mathematics

1 answer:

tino4ka555 [31]3 years ago

3 0

X^2 is x times x, and since x is 2, it's 2 times 2 which equals 4.

The answer is 4.

Hope this helped! If you have anymore questions or don't understand, please comment or DM me. :)

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tiny-mole [99]

Answer:

$x=\frac{\sqrt{14} }{2}$

Step-by-step explanation:

Notice that you are given an isosceles right-angle triangle to solve, since each of its two acute angles measures $45^o$ . Then such means that the sides opposite to these acute angles (the so called "legs" of this right angle triangle) must also be of the same length (x).

We can then use the Pythagorean theorem that relates the square of the hypotenuse to the addition of the squares of the triangles legs:

$(\sqrt{7})^2=x^2+x^2\\7=2\,x^2\\x^2=\frac{7}{2} \\x=+/-\sqrt{\frac{7}{2}} \\x=+/-\frac{\sqrt{14} }{2}$

We use just the positive root, since we are looking for an actual length. then, the requested side is:

$x=\frac{\sqrt{14} }{2}$

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Step-by-step explanation:

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