It’s a little complicated but here’s how it works:
Imagine a table with the intervals
0:4 , 4:6 , 6:7 , 7:10 , 10:13 (10 year intervals)
Then we have different rows
Class width: 4 , 2 , 1 , 3 , 3
Freq density: 0.2 , 0.5 , 1.2 , 0.7 , 0.3
So now calculate frequency where freq = class width * density
Freq: 0.8 , 1 , 3.6 , 2.1 , 0.9
So to find median find cumulative frequency
(Add all freq)
Cfreq = 8.4 now divide by 2 = 4.2
So find the interval where 4.2 lies.
0.8 + 1 = 1.8 + 3.6 = 5.6
So 4.2 (median) will lie in that interval 60-70 years.
Answer: 1,365 possible special pizzas
Step-by-step explanation:
For the first topping, there are 15 possibilities, for the second topping, there are 14 possibilities, for the third topping, there are 13 possibilities, and for the fourth topping, there are 12 possibilities. This is how you find the number of possible ways.
15 * 14 * 13 * 12 = 32,760
Now, you need to divide that by the number of toppings you are allowed to add each time you add a topping.
4 * 3 * 2 * 1 = 24
32,760 / 24 = 1,365
There are 1,365 possible special pizzas
Answer: y = 1
so 1! hopefully I helped!
Step-by-step explanation:
the area would be 4 times more
so 135 x 4 = 540
Answer:
a. Mean = £27928.57
b. Mean without Deva's income = £19416.67
Step-by-step explanation:
The mean is calculated by dividing the sum of values by number of values. Given 7 values will be used to calculate mean.
So,
Number of values = n = 7
Now,
Rounding off to two decimal places
Mean income = £27928.57
Now we have to calculate mean without Deva's income so the number of values will be 6 and the sum will be:
The mean without Deva's income is:
Rounding off to 2 DP
Mean = £19416.67
Hence,
a. Mean = £27928.57
b. Mean without Deva's income = £19416.67
