Answer:
<span>y=<span><span><span>log<span>(x)</span></span>−<span>log<span>(50000)</span></span></span><span>log<span>(0.8)</span></span></span></span>
Explanation:
write as : <span>y=50000<span><span>(0.8)</span>x</span></span>
Taking logs:
<span><span>log<span>(y)</span></span>=<span>log<span>(50000)</span></span>+<span>log<span>(.<span><span>(0.8)</span>x</span>.)</span></span></span>
But <span>log<span>(.<span><span>(0.8)</span>x</span>.)</span></span> is the same as <span>x<span>log<span>(0.8)</span></span></span>
Thus
<span>x=<span><span><span>log<span>(y)</span></span>−<span>log<span>(50000)</span></span></span><span>log<span>(0.8<span>)
</span></span></span></span></span>Now swap the x'x and the y's giving:<span><span><span><span><span>
</span></span></span></span></span>
<span>y=<span><span><span>log<span>(x)</span></span>−<span>log<span>(50000)</span></span></span><span>log<span>(0.8<span>)
my teacher helped a little bit
</span></span></span></span></span>
Answer:
Graph D
Step-by-step explanation:
it does not pass the linear test to qualify as a function
390.20 is the answer because 4%of 2880 is 115.20 plus 275.00 is 390.20
Answer:
450,000
This is because 400,000 and 500,000 have no other numbers that could be the middle, so it has to be directly in-between both numbers.
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Questions related to this topic? Please ask me in the <em>comments</em> box.
A could be 2 while B could be 3, so -2a+3b turns into -4+9, which equals 5.
From what I know you can't really solve a a single equation with two-variables so it's just a matter of trial and error.
Just try plugging in a small number like 2 for a just to try it and you get 8b^2=72.
Divide everything by 8 to isolate b and you get that b^2=9.
Square root everything and you'll find that b=3. This is just one possible combination, I'm sure there are many more but this is obviously the one that was intended to be found.
Now that we know that a=2 and b=3 just plug them into the equation.
-2(2)+3(3)=?
-4+9=?
5
Sorry about having to use this ^ symbol, the equation maker is not working.
