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Kay [80]
3 years ago
12

The formula c = √a^2 + b^2 represents the length of the hypotenuse of a right triangle with side lengths a and b. Solve the equa

tion for b. Show your work.
Mathematics
1 answer:
Eduardwww [97]3 years ago
7 0

Answer:

b = √(c^2 - a²)

Step-by-step explanation:

Start with the given c = √a^2 + b^2.  Squaring both sides, we get:

c² = a² + b².

We want to iosolate b² and then b.

So:  subtract a² from both sides, resulting in:

c² - a² = b²

Taking the square root of both sides, we get:

√b² = √(c² - a²)

and so:

b = √(c^2 - a²)

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Write the property that matches the equation.<br> 3+(4+7)=(3+4)+7
miss Akunina [59]

Answer:

associative property

Step-by-step explanation:

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2 years ago
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Use any of the methods to determine whether the series converges or diverges. Give reasons for your answer.
Aleks [24]

Answer:

It means \sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6} also converges.

Step-by-step explanation:

The actual Series is::

\sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6}

The method we are going to use is comparison method:

According to comparison method, we have:

\sum_{n=1}^{inf}a_n\ \ \ \ \ \ \ \ \sum_{n=1}^{inf}b_n

If series one converges, the second converges and if second diverges series, one diverges

Now Simplify the given series:

Taking"n^2"common from numerator and "n^6"from denominator.

=\frac{n^2[7-\frac{4}{n}+\frac{3}{n^2}]}{n^6[\frac{12}{n^6}+2]} \\\\=\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{n^4[\frac{12}{n^6}+2]}

\sum_{n=1}^{inf}a_n=\sum_{n=1}^{inf}\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\ \ \ \ \ \ \ \ \sum_{n=1}^{inf}b_n=\sum_{n=1}^{inf} \frac{1}{n^4}

Now:

\sum_{n=1}^{inf}a_n=\sum_{n=1}^{inf}\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\\ \\\lim_{n \to \infty} a_n = \lim_{n \to \infty}  \frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\\=\frac{7-\frac{4}{inf}+\frac{3}{inf}}{\frac{12}{inf}+2}\\\\=\frac{7}{2}

So a_n is finite, so it converges.

Similarly b_n converges according to p-test.

P-test:

General form:

\sum_{n=1}^{inf}\frac{1}{n^p}

if p>1 then series converges. In oue case we have:

\sum_{n=1}^{inf}b_n=\frac{1}{n^4}

p=4 >1, so b_n also converges.

According to comparison test if both series converges, the final series also converges.

It means \sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6} also converges.

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How do you find the lateral surface area of a cylinder?
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Right cylinderSolve for lateral surfaceAL=2πrh<span><span><span>rRadius</span><span>hHeight</span></span><span><span>h</span>
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Use the substitution method to solve the system of equations
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You solve the substitution method to solve a system of equality by expressing one variable in terms of the other using one equation, and then plugging this expression in the other(s).

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