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mario62 [17]
3 years ago
12

I really need help Please help me please

Mathematics
1 answer:
Jlenok [28]3 years ago
4 0
I think the answer is 35.28 square units. Because triangle ABC is 1/2 of triangle XYZ, the height must be halved. So, 3.36/2 is 1.68. Now, you times 42 by 1.68 to get 70.56. Then, divide that by 2 to get 35.28
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The sum of two polynomials is 10a^2b^2-8a^2b+6ab^2-4ab+2 if one addend is -5a^2b^2+12a^2b-5 what is the other addend
spayn [35]

Answer:

The other addend is 15\cdot a^{2}\cdot b^{2}-20\cdot a^{2}\cdot b + 6\cdot a \cdot b^{2}-4\cdot a \cdot b +7.

Step-by-step explanation:

The other addend is determined by subtracting -5\cdot a^{2}\cdot b^{2}+12\cdot a^{2}\cdot b-5 from 10\cdot a^{2}\cdot b^{2}-8\cdot a^{2}\cdot b + 6\cdot a\cdot b^{2}-4\cdot a \cdot b + 2:

x = 10\cdot a^{2}\cdot b^{2}-8\cdot a^{2}\cdot b + 6\cdot a \cdot b^{2}-4\cdot a \cdot b + 2 - (-5\cdot a^{2}\cdot b^{2}+12\cdot a^{2}\cdot b -5)

x = 10\cdot a^{2}\cdot b^{2}-8\cdot a^{2}\cdot b + 6\cdot a \cdot b^{2}-4\cdot a \cdot b +2 +5\cdot a^{2}\cdot b^{2}-12\cdot a^{2}\cdot b+5

x = (10\cdot a^{2}\cdot b^{2}+5\cdot a^{2}\cdot b^{2})-(8\cdot a^{2}\cdot b+12\cdot a^{2}\cdot b)+6\cdot a \cdot b^{2}-4\cdot a \cdot b +7

x = 15\cdot a^{2}\cdot b^{2}-20\cdot a^{2}\cdot b + 6\cdot a \cdot b^{2}-4\cdot a \cdot b +7

The other addend is 15\cdot a^{2}\cdot b^{2}-20\cdot a^{2}\cdot b + 6\cdot a \cdot b^{2}-4\cdot a \cdot b +7.

6 0
3 years ago
Help mee<br> please.......................... :3 :3
cluponka [151]
14) Since f=5, f + 69 = 74
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5 0
3 years ago
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Answer: I think it helps with the square units that both squares have.

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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