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vlada-n [284]
3 years ago
11

Help, please ? Thank you so much in advance and I'd appreciate it!

Mathematics
2 answers:
Darina [25.2K]3 years ago
7 0
First you calculate the area of the big rectangle (ignoring the small one the bottom):

A1 = 10 x 6 = 60.

next you calculate the small one:

A2 = 2 x 2 = 4

Now you subtract the small one from the big one and you get:

Area of the figure = A1 - A2 = 60 - 4 = 56
hoa [83]3 years ago
3 0
To start off, pretend it's a quadrilateral. It makes everything easier and uses all the numbers.

The area of a quadrilateral is base times height. 
10 = base 
6 = height 

6 * 10 = 60 

That's the value of the original, larger, quadrilateral without the mini quadrilateral that we have to subtract. 

The dimensions of the height and base of the mini quadrilateral are 2 by 2. 
2 * 2 = 4 

Subtract to get your answer: 
60 - 4 = 56


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What property is -3(m+8)=-3m-24
Damm [24]

Answer:

All real numbers are solutions.

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

−3(m+8)=−3m−24

(−3)(m)+(−3)(8)=−3m+−24(Distribute)

−3m+−24=−3m+−24

−3m−24=−3m−24

Step 2: Add 3m to both sides.

−3m−24+3m=−3m−24+3m

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Step 3: Add 24 to both sides.

−24+24=−24+24

0=0

Answer:

All real numbers are solutions.

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3 years ago
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3 years ago
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Find the equation of the parallel to the line 3x-2y=5 and passing through the midpoint of the line segment joining the points (-
levacccp [35]

Given:

The equation of parallel line is:

3x-2y=5

The required line passing through the midpoint of the line segment joining the points (-4,2) and (2,4).​

To find:

The equation of required line.

Solution:

Midpoint of  line segment joining the points (-4,2) and (2,4) is:

Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)

Midpoint=\left(\dfrac{-4+2}{2},\dfrac{2+4}{2}\right)

Midpoint=\left(\dfrac{-2}{2},\dfrac{6}{2}\right)

Midpoint=\left(-1,3\right)

It means the required line passes through the point (-1,3).

The slope of line Ax+By=C is:

m=\dfrac{-A}{B}

The given equation is:

3x-2y=5

Here, A=3 and B=-2. So, the slope of the line is:

m=\dfrac{-3}{-2}

m=1.5

Slope of parallel lines are same. So, the slope of the required line is 1.5.

The required line passes through the point (-1,3) with slope 1.5. So, the equation of the line is:

y-y_1=m(x-x_1)

y-3=1.5(x-(-1))

y-3=1.5(x+1)

y-3=1.5x+1.5

Adding 3 on both sides, we get

y=1.5x+1.5+3

y=1.5x+4.5

Therefore, the equation of the required line is y=1.5x+4.5.

8 0
3 years ago
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