The product of a <em>complex</em> number and its conjugate is (a + i b) · (a - i b), where a and b are <em>real</em> numbers, and the result for the <em>complex</em> number 2 + i 3 is 13.
<h3>What is the multiplication of a complex number and its conjugate</h3>
Let be a <em>complex</em> number a + i b, whose conjugate is a - i b. Where a and b are <em>real</em> numbers. The product of these two numbers is:
(a + i b) · (a - i b)
Then, we proceed to obtain the result by some algebraic handling:
a · (a + i b) + (- i b) · (a + i b)
a² + i a · b - i a · b - i² b²
a² - i² b²
a² + b²
If we know that a = 2 and b = 3, then the product of the complex number and its conjugate is:


To learn more on complex numbers: brainly.com/question/10251853
#SPJ1
Given:
Cylinder: radius = 8 yd; height = 4 yd
Surface Area = 2 π r h + 2 π r²
SA = 2 * 3.14 * 8 yd * 4yd + 2 * 3.14 * (8yd)²
SA = 200.96 yd² + 401.92 yd²
SA = 602.88 yd²
Volume = π r² h
V = 3.14 * (8yd)² * 4yd
V = 803.84 yd³
Dimension is cut in half. radius = 4yds ; height = 2yds
S.A = 2 * 3.14 * 4yd * 2yd + 2 * 3.14 * (4yd)²
S.A = 50.24 yd² + 100.48 yd²
SA = 150.72 yd²
V = 3.14 * (4yd)² * 2yd
V = 100.48 yd³
SA = 602.88 yd² - 150.72yd² = 452.16 yd²
V = 803.84 yd³ - 100.48 yd³ = 703.36 yd³
Answer:
C. 5^8
to raise a power to another power, multiply the exponents
then multiply thr numbers
then u get 5^8
The answer is B. Y^7. u have to add the exponent
The formula of simple intrest is:
p × r × t