Answer:
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Step-by-step explanation:
Answer:
Step-by-step explanation:
![{ \tt{\int\limits^2_1 {x^{2}-8x+8 } \, dx}} \\ \\ = { \tt{[ \frac{ {x}^{3} }{3} - 4 {x}^{2} + 8x ] {}^{2} _{1}}}](https://tex.z-dn.net/?f=%7B%20%5Ctt%7B%5Cint%5Climits%5E2_1%20%7Bx%5E%7B2%7D-8x%2B8%20%7D%20%5C%2C%20dx%7D%7D%20%5C%5C%20%20%5C%5C%20%3D%20%20%7B%20%5Ctt%7B%5B%20%5Cfrac%7B%20%7Bx%7D%5E%7B3%7D%20%7D%7B3%7D%20%20-%204%20%7Bx%7D%5E%7B2%7D%20%20%2B%208x%20%5D%20%7B%7D%5E%7B2%7D%20_%7B1%7D%7D%7D)
Substitute x with the limits:
I'm pretty sure this answer is A or D
If not then I don't know it but I'll try to help you out
Answer:
The values of x and y are x = 6 and y = 9Step-by-step explanation:
MNOP is a parallelogram its diagonal MO and PN intersected at point A
In any parallelogram diagonals:
Bisect each other
Meet each other at their mid-point
In parallelogram MNOP
∵ MO and NP are its diagonal
∵ MO intersect NP at point A
- Point A is the mid-point pf them
∴ MO and NP bisect each other
∴ MA = AO
∴ PA = AN
∵ MA = x + 5
∵ AO = y + 2
- Equate them
∴ x + 5 = y + 2 ⇒ (1)
∵ PA = 3x
∵ AN = 2y
- Equate them
∴ 2y = 3x
- Divide both sides by 2
∴ y = 1.5x ⇒ (2)
Now we have a system of equations to solve it
Substitute y in equation (1) by equation (2)
∴ x + 5 = 1.5x + 2
- Subtract 1.5x from both sides
∴ - 0.5x + 5 = 2
- Subtract 5 from both sides
∴ - 0.5x = -3
- Divide both sides by - 0.5
∴ x = 6
- Substitute the value of x in equation (2) to find y
∵ y = 1.5(6)
∴ y = 9
The values of x and y are x = 6 and y = 9
We have been given that in ΔRST, the measure of ∠T=90°, SR = 65, TS = 33, and RT = 56. We are asked to find the value of sine of ∠R to the nearest hundreth.
First of all, we will draw a right triangle using our given information.
We know that sine relates opposite side of right triangle to hypotenuse.
We can see that side SR is hypotenuse and TS is opposite side to angle R.
Upon rounding to nearest hundredth, we will get:
Therefore, the value of the sine of ∠R is approximately 1.97.
