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Alina [70]
3 years ago
8

Please help me with this please

Mathematics
2 answers:
kodGreya [7K]3 years ago
8 0

Answer:i think its the The second

Step-by-step explanation:   so  look 2x6=12 and 4x2=8 so the snswers are on the right and the question is on the left holpfuly that helps

AleksandrR [38]3 years ago
7 0

Answer: The second to last option I think

Step-by-step explanation:

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Write a recursive rule for an= Зn — 6.
mart [117]

Answer:

Explicit formula: a(n)=3n-6

Recursive formula: a(n)=-3+(n-1)3 <--

Step-by-step explanation:

a(n)=3n-6 where a(1)=3(1)-6=-3 and d=3

<u>Plug values into recursive formula:</u>

a(n)=a1+(n-1)d

a(n)=-3+(n-1)3

8 0
3 years ago
What is 3 to the power of 8 divided by 3 to the power of 2
Troyanec [42]

Answer:

729

Step-by-step explanation:

hope this helps!

3 0
3 years ago
Read 2 more answers
IS the decimal number 5.078, the digit in the hundredths place is a 7.<br>TRUE OR FALSE?????
Ksju [112]

Answer:

TRUE

The 7 is in the hundredths place

The 0 is in the tenths place

The 8 is in the thousandths place

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Ab=6cm<br> Ac=12cm<br> Calculate the length of CD
KatRina [158]

Answer:

12.7 cm

Step-by-step explanation:

ABC

12² = 6² + BC²

12² - 6² = BC²

144 - 36 = 108

CB² = 108

√108 = 10.392

CB = 10.392

CBD

Sin (55°) = CB / CD

0.81915 = √108 / CD

CD = 10.392 / 0.81915

CD = 12.686

CD = 12.7cm

3 0
3 years ago
A health psychologist knew that corporate executives in general have an average score of 2.55 with a standard deviation of 0.5 o
Mumz [18]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the following :

Population mean (μ) = 2.55

Population standard deviation (σ) = 0.5

Sample size (n) = 30

Sample mean (x) = 2.76

α = 0.05

STEP 1:

Stress score in general executive (s1)

Stress score in exercising executive (s2)

Null : s1 = s2

Alternative : s1 < s2

STEP 2:

Shape of distribution = normal

Population mean (μ) = 2.55

Population standard deviation (σ) = 0.5

Sample size (n) = 30

Sample mean (x) = 2.76

α = 0.05

Decision rule :

α = 0.05 which corresponds to a t score (t0) ;

df = n - 1 = 30 - 1= 30 at 0.05 = 1.699

If :

(Test statistic (t) > t0) ; reject the Null

(right tailed test)

Test statistic (t) :

(x - μ) / (σ/√n)

(2.76 - 2.55) / (0.5/√30)

0.21 / 0.0913

= 2.30

t > t0

2.30 > 1.699

t is more extreme than t0

Hence, reject the null at α = 0.05

7 0
3 years ago
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