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4 years ago

11

Pete is purchasing a smart phone for $249.30 he gives the sales clerks 3 fifty-dollar bills 4 twenty-dollar bills, and 4 five-do

llar bills. how much should he receive in change

2 answers:

likoan [24]4 years ago

8 0

The answer would be 0.7

marin [14]4 years ago

3 0

3 • 50 = 150
4 • 20 = 80
4 • 5 = 20
150 + 80 + 20 = 250
250 - 249.30 = 0.70

So Pete should receive $0.70 in change.

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A scale model of the Vancouver Olympic cauldron is to be built in memory of the 2010 Olympics. If the scale to be used is 1:27,

timurjin [86]

Answer:

23/54 meters

Step-by-step explanation:

Assuming that the scale model is smaller, then the scale model should be 1/27th of the actual thing. Therefore:

11.5/27

= 23/54 meters tall

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4 years ago

Solve the following quadratic equation by factoring or Quadratic Formula.

s344n2d4d5 [400]

Answer:

A.

Step-by-step explanation:

x2 - 3x - 10. = 0

x2 + 2x - 5x - 10 = 0

(x2 + 2x) (-5x - 10) = 0

x (x + 2) - 5 (x + 2) = 0

(x - 5) (x + 2) = 0

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6 0

3 years ago

Read 2 more answers

The units’ digit of a two-digit number is 7 more than the tens’ digit. If 26 is added to the number, the result obtained is five

Vikki [24]

Let the digit in the tens place be x

tens place = x (therefore the value is 10x)
ones place = x + 7
The number is 10x + x + 7

Add 26 to it
10x + x + 7 + 26 = 11x + 33

It is 5 times the sum of the digit
11x + 33 = 5(x + x + 7)
11x 33 = 10x + 35
x = 2
x+ 7 = 2 + 7 = 9

So the number is 29

3 0

3 years ago

Which answer is it I’m doing my quiz rn

anyanavicka [17]

Answer:

10

Step-by-step explanation

3 x 4 = 12

8 + 12 = 20

20 / 2 = 10

8 0

3 years ago

Read 2 more answers

i f N(-7,-1) is a point on the terminal side of ∅ in standard form, find the exact values of the trigonometric functions of ∅.

Natali [406]

Answer:

$sin\ \varnothing = \frac{-1}{10}\sqrt 2$

$cos\ \varnothing = \frac{-7}{10}\sqrt 2$

$tan\ \varnothing = \frac{1}{7}$

$cot\ \varnothing = 7$

$sec\ \varnothing = \frac{-5}{7}\sqrt 2$

$csc\ \varnothing = -5\sqrt 2$

Step-by-step explanation:

Given

$N = (-7,-1)$ --- terminal side of $\varnothing$

Required

Determine the values of trigonometric functions of $\varnothing$ .

For $\varnothing$ , the trigonometry ratios are:

$sin\ \varnothing = \frac{y}{r}$ $cos\ \varnothing = \frac{x}{r}$ $tan\ \varnothing = \frac{y}{x}$

$cot\ \varnothing = \frac{x}{y}$ $sec\ \varnothing = \frac{r}{x}$ $csc\ \varnothing = \frac{r}{y}$

Where:

$r^2 = x^2 + y^2$

$r = \sqrt{x^2 + y^2$

In $N = (-7,-1)$

$x = -7$ and $y = -1$

So:

$r = \sqrt{(-7)^2 + (-1)^2$

$r = \sqrt{50$

$r = \sqrt{25 * 2$

$r = \sqrt{25} * \sqrt 2$

$r = 5 * \sqrt 2$

$r = 5 \sqrt 2$

<u>Solving the trigonometry functions</u>

$sin\ \varnothing = \frac{y}{r}$

$sin\ \varnothing = \frac{-1}{5\sqrt 2}$

Rationalize:

$sin\ \varnothing = \frac{-1}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$sin\ \varnothing = \frac{-\sqrt 2}{5*2}$

$sin\ \varnothing = \frac{-\sqrt 2}{10}$

$sin\ \varnothing = \frac{-1}{10}\sqrt 2$

$cos\ \varnothing = \frac{x}{r}$

$cos\ \varnothing = \frac{-7}{5\sqrt 2}$

Rationalize

$cos\ \varnothing = \frac{-7}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$cos\ \varnothing = \frac{-7*\sqrt 2}{5*2}$

$cos\ \varnothing = \frac{-7\sqrt 2}{10}$

$cos\ \varnothing = \frac{-7}{10}\sqrt 2$

$tan\ \varnothing = \frac{y}{x}$

$tan\ \varnothing = \frac{-1}{-7}$

$tan\ \varnothing = \frac{1}{7}$

$cot\ \varnothing = \frac{x}{y}$

$cot\ \varnothing = \frac{-7}{-1}$

$cot\ \varnothing = 7$

$sec\ \varnothing = \frac{r}{x}$

$sec\ \varnothing = \frac{5\sqrt 2}{-7}$

$sec\ \varnothing = \frac{-5}{7}\sqrt 2$

$csc\ \varnothing = \frac{r}{y}$

$csc\ \varnothing = \frac{5\sqrt 2}{-1}$

$csc\ \varnothing = -5\sqrt 2$

3 0

3 years ago