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Komok [63]
3 years ago
11

Assuming an initial bracket of [1, 5] for bisection method, the first (at the end of 1 iteration) iterative value of the root of

((te)^-t)-.3=0 is?
Mathematics
1 answer:
BartSMP [9]3 years ago
4 0

Answer:

After 1 iteration the value if the root will be α=3

Step-by-step explanation:

Bisection takes the interval and selects the value in the middle of the interval as the root, then compares signes with the previous extremes of the interval.

\alpha _1=\frac{(b-a)}{2}+a=\frac{5-1}{2}+1=3

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Okay, I know fractions are scary, but we can do this alright?

First, you see the whole number on the side? Get that first.

10- 5 = 5

now we have 5 left and a scary fraction.  Don't panic, let's do this.  We know 1 is 3/3.  1 can be anything as long as the number on top and the number at the bottom are the same then it would be one.

So 3/3 is one then we can subtract:

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As you took one away from the 5, it becomes a 4 and you put back the left over, 1/3.

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8 0
3 years ago
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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