Assuming an initial bracket of [1, 5] for bisection method, the first (at the end of 1 iteration) iterative value of the root of

Question

Komok [63]

3 years ago

11

Assuming an initial bracket of [1, 5] for bisection method, the first (at the end of 1 iteration) iterative value of the root of

((te)^-t)-.3=0 is?

Mathematics

1 answer:

BartSMP [9] · Answer 1 · 2022-07-21T06:52:08+03:00

BartSMP [9]3 years ago

4 0

Answer:

After 1 iteration the value if the root will be α=3

Step-by-step explanation:

Bisection takes the interval and selects the value in the middle of the interval as the root, then compares signes with the previous extremes of the interval.

$\alpha _1=\frac{(b-a)}{2}+a=\frac{5-1}{2}+1=3$