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d1i1m1o1n [39]
2 years ago
12

Write an expression that represents the perimeter of the triangle.

Mathematics
1 answer:
uysha [10]2 years ago
7 0

Answer:

(3m - 2) + (2m + 7) + (5m - 3)

Step-by-step explanation:

Perimeter is found by combining all side measurements together to find the total measurement. In this case, combine the sides:

(3m - 2) + (2m + 7) + (5m - 3) is your answer.

If you need a simplified expression, simply combine all the like terms together. Like terms are terms with the same as well as same amount of variables:

(3m + 2m + 5m) + (7 - 2 - 3)

(10m) + (2)

10m + 2 is your answer.

~

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Find the degree of this polynomial<br> -7b2 + b + 6
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The degree of a polynomial is the highest power.

In the polynomial we are given, the only power is 2 which makes it greatest.

Therefore, the degree is 2.

Best of Luck!

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f(x) is a quadratic function with x-intercepts at (−1, 0) and (−3, 0). If the range of f(x) is [−4, [infinity]) and g(x) = 2x^2
iren2701 [21]

Answer with Step-by-step explanation:

We are given that function f(x) which is quadratic function.

x -intercept of function f(x) at (-1,0) and (-3,0)

x-Intercept of f means zeroes of f

x=-1 and x=-3

Range of f =[-4,\infty)

g(x)=2x^2+8x+6=2(x^2+4x+3)

g(x)=0

2(x^2+4x+3)=0

x^2+4x+3=0

x^2+3x+x+3=0

x(x+3)+1(x+3)=0

(x+1)(x+3)=0

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Therefore, x-intercept of g(x) at (-1,0) and (-3,0).

Substitute x=-2

g(-2)=2(-2)^2+8(-2)+6=8-16+6=-2

g(x)=2(x^2+4x)+6

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g(x)=2(x+2)^2-2

By comparing with the equation of parabola

y=a(x-h)^2+k

Where vertex=(h,k)

We get vertex of g(x)=(-2,-2)

Range of g(x)=[-2,\infty)

Zeroes of f and g are same .

But range of f and g are different.

Range of f contains -3 and -4 but range of g does not contain -3 and -4.

f and g are both quadratic functions.

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3 years ago
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Answer:

Step-by-step explanation:

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