Can some help me out

Mathematics

1 answer:

julia-pushkina [17]3 years ago

8 0

Sure, what do you need help with?

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What are 26 divide by 4,340

mart [117]

$\frac { 26 }{ 4,340 } \\ \\ =\frac { 26 }{ 4\cdot { 10 }^{ 3 }+3\cdot { 10 }^{ 2 }+4\cdot { 10 }^{ 1 } } \\ \\ =\frac { 26 }{ 10\left( 4\cdot { 10 }^{ 2 }+3\cdot { 10 }^{ 1 }+4 \right) } \\ \\ =\frac { 2\cdot 13 }{ 2\cdot 5\left( 4\cdot { 10 }^{ 2 }+3\cdot { 10 }^{ 1 }+4 \right) } \\ \\ =\frac { 13 }{ 5\left( 4\cdot { 10 }^{ 2 }+3\cdot { 10 }^{ 1 }+4 \right) }$

$\\ \\ =\frac { 13 }{ 5\left( 400+30+4 \right) } \\ \\ =\frac { 13 }{ 2,000+150+20 } \\ \\ =\frac { 13 }{ 2,170 }$

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13/2170 = 0.006 (to 3 decimal places)

4 0

3 years ago

Read 2 more answers

r. Rita needs to replace the ink cartridge for her printer. She found four brands that make replacement cartridges. The table be

Scilla [17]

B Im not 100% sure but I hope I could help

3 0

3 years ago

A sample of tritium-3 decayed to 94.5% of its original amount after a year.

Zolol [24]

(a) If $y(t)$ is the mass after $t$ days and $y(0) = A$ then $y(t) = Ae^{kt}.$

$y(1) = Ae^k = 0.945A \implies e^k = 0.945 \implies k = \ln 0.945$

$\text{Then } Ae^{(\ln 0.945)t} = \frac{1}{2}A\ \Leftrightarrow\ \ln e^{(\ln 0.945)t} = \ln \frac{1}{2}\ \Leftrightarrow\ ( \ln 0.945) t = \ln \frac{1}{2} \Leftrightarrow \\ \\
t = - \frac{\ln 5}{\ln 0.945} \approx 12.25 \text{ years}$

(b)
$Ae^{(\ln 0.945) t} = 0.20 A \ \Leftrightarrow\ (\ln 0.945) t \ln \frac{1}{5}\ \implies \\ \\
t = - \frac{\ln 5}{\ln 0.945} \approx 28.45\text{ years}$