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Feliz [49]
3 years ago
14

9x^2 - 8x - 1 = 0 What are the x intercepts?

Mathematics
1 answer:
sasho [114]3 years ago
4 0
9x^2  - 8x - 1 = 0

(9x + 1(x - 1) = 0

x = -1/9 , 1  

x intercepts are -1/9 and 1.
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RSB [31]

k = 13The smallest zero or root is x = -10

===============================

Steps:

note: you can write "x^2" to mean "x squared"

f(x) = x^2+3x-10

f(x+5) = (x+5)^2+3(x+5)-10 ... replace every x with x+5

f(x+5) = (x^2+10x+25)+3(x+5)-10

f(x+5) = x^2+10x+25+3x+15-10

f(x+5) = x^2+13x+30

Compare this with x^2+kx+30 and we see that k = 13

Factor and solve the equation below

x^2+13x+30 = 0

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x+1 = 0 or x+3 = 0

x = -10 or x = -3

The smallest zero is x = -10 as its the left-most value on a number line.

Please mark brainliest

<em><u>Hope this helps.</u></em>

3 0
3 years ago
PLEASE HELPP!
zheka24 [161]

Answer:

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Height x pi(3.14 or 22/7 depending what they tell you to use for pi) x radius being squared (your radius is half of your diameter or given radius).

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3 years ago
Read 2 more answers
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