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lys-0071 [83]
3 years ago
12

Copy the proof on paper, mark the givens in the diagram, and fill in the blanks to complete the proof.

Mathematics
2 answers:
steposvetlana [31]3 years ago
8 0

Answer:

Step-by-step explanation:

Too hard for me to answer, sorry

ExtremeBDS [4]3 years ago
4 0

im really sorry this is so late oof

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Answer plzzzz asappp !!
Scorpion4ik [409]
N + 7 > (or equal to) 53 is the answer 
4 0
4 years ago
Thomas uses 8 ounces of sugar to make 36 fluid ounces of lemonade, how many ounces of sugar will he use?
sergij07 [2.7K]

Answer:

8

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
The expression -320+15y represents a submarine that began at a depth of 15 feet below sea level and ascended at a rate of feet p
alex41 [277]

Step-by-step explanation:

Given an expression that represents a submarine that began at a depth of 15 feet below sea level and ascended at a rate of feet per minute is as follows :

-320+15y

We need to find the depth of submarine after 15 ​minutes.

Put y = 15 in the above expression.

-320+15y = -320+15(15)

= -320 + 225

= -95

Hence, the submarine is below sea level at 95 feet.

4 0
3 years ago
If k stands for an integer, then is it possible for k2 + k to stand for an odd integer? Be prepared to justify your answer.
BartSMP [9]

Answer:

<em>k^2 + k never stands for an odd integer</em>

Step-by-step explanation:

Let us consider either case with which k stands for an odd or even integer;

Case 1: k is an odd integer

For integer a, k = 2a + 1

So, k + 1 = 2a + 2 = 2( a + 1 ) = 2b for integer b

k^2 + k = k ( k + 1 ) = k ( 2b ) = 2kb = 2c for integer c,

<em>Therefore, if k is an odd integer, then k^2 + k is an even integer ;</em>

Case 2: k is an even integer

For an integer a, k = 2a

So, k + 1 = 2a + 1

k^2 + k = k( k+1 ) = 2a( 2a + 1 ) , multiple of 2

<em>Therefore, if k is an even integer, then k^2 + k is an even integer;</em>

<em>This would make k^2 + k never stand for an odd integer</em>

5 0
3 years ago
for a normal distribution curve with the mean of 15 and a standard deviation of 5, which range of the variable defines an area u
kipiarov [429]
Using empirical rule,
Upper range of 68%=15+5=20
Lower range =10
Range=10
8 0
3 years ago
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