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Rudik [331]
3 years ago
8

A football team gained 12 yards on one play, lost 40 yards on another, and gained 34 yards on the last play of the first half. T

hey had already gained 345 already during the half. What was the total yardage gain for the first half?
Mathematics
1 answer:
ale4655 [162]3 years ago
6 0
It would be 345+12=357, then 357-40=317, and finally,317+34=351
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Part of a city map is shown. If m 5 = x, which angles also have a measure of x? Select all that apply.
Evgesh-ka [11]

Answer:

C 9

D 12

Step-by-step explanation:

9 is a corresponding angle to 5 and 12 is an opposite angle to 9

Also by convention, grid lines are at right angles to each other so 5, 6, 7, 8, 9, 10, 11, and 12 are all equal at x = 90°

7 0
2 years ago
I need help please?!!!!
Naya [18.7K]

Answer:

What you put is correct

Step-by-step explanation:

Because it is -3 and its pointing to the right so the arrow would be like that.

8 0
3 years ago
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At midnight, the temperature was 30 degrees Fahrenheit. By 6:00 am, IT had dropped 5 degrees Fahrenheit and by noon, it had incr
Allisa [31]
At noon, the temperature was 36 degrees. At midnight, the temperature was 30 degrees. By 6:00 am it drooped 5 degrees. Since it dropped 5 degrees, you subtract 5 from 30, which equals 25. It then increased by 11 degrees. Since the temperature increased, you add 11 to 25, which equals 36. At noon, the temperature was 36 degrees.
4 0
3 years ago
Help please you don’t know how much this means to me
ICE Princess25 [194]
<h2>Problem 6:</h2><h2>a)</h2>

a(0) = 1  \:  \:  \:  \:  \:  \: b(0) = 2 \:  \:  \:  \:  \: c(0) = 3 \\ a(1) = b(0) + c(0) = 2 + 3 = 5 \\ b(1) = a(0) + c(0) = 1 + 3 = 4 \\ c(1) = a(0) + b(0) = 1 + 2 = 3 \\  \\ a(2) = b(1) + c(1) = 4 + 3 = 7 \\ b(2) = a(1) + c(1) = 5 + 3 = 8 \\ c(2) = a(1) + b(1) = 5 + 4 = 9

a(3) = b(2) + c(2) =  8 + 9 = 17\\ b(3) = a(2) + c(2) =7 + 9 = 16  \\ c(3) = a(2) + b(2) = 7 + 8 = 15 \\  \\ a(4) = b(3) + c(3) = 16  + 15 = 31 \\ b(4) = a(3) + c(3) = 17 + 15 = 32 \\ c(4) = a(3) + b(3) = 17 + 16 = 33

a(5) = 32 + 33 = 65 \\ b(5) = 31 + 33 = 64 \\ c(5) =31 + 32 =  63 \\  \\ a(6) = 64 + 63 = 127 \\ b(6) = 65 + 63 = 128 \\ c(6) = 65 + 64 = 129 \\

a(7) = 128 + 129 = 257 \\ b(7) = 127 + 129 = 256 \\c (7) = 127 + 128 = 255 \\  \\ a(8) = 256 + 255 = 511 \\ b(8) = 257 + 255 = 512 \\ c(8) = 257 + 256 = 513

a(9) = 512 + 513 = 1025 \\ b(9) = 511 + 513 = 1024 \\ c(9) = 511 + 512 = 1023 \\  \\ a(10) = 1024 + 1023 = 2047 \\ b(10) = 1025  + 1023 = 2048 \\ c(10) = 1025 + 1024 = 2049

<h2>b)</h2>

a(n) + b(n) + c(n) =   \\  2(a(n - 1) + b(n - 1) + c(n - 1)) \\   6 \times 2 {}^{n }

<h2>c)</h2>

6 \times 2 {}^{n}  > 100 \: 000 \\ 2 {}^{n}  >  \frac{100 \: 000}{6}  \\ n >  log {}^{2} ( \frac{100 \: 000}{6} )  \\ n > 14.02468 \\ n = 15

<h2 />
5 0
1 year ago
4/5 divided by 16/15 to lowest terms
liraira [26]

Answer:

3/4

Step-by-step explanation:

4/5 ÷ 16/15

To divide by a fraction, multiply by the reciprocal.

4/5 × 15/16

Switch the numerators.

15/5 × 4/16

Reduce each fraction.

3/1 × 1/4

Multiply.

3/4

7 0
3 years ago
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