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Angle measure labeled a The arc mesure labeled c

inna [77]

Step-by-step explanation:

angle measure a =48/2=24°

the arc measure =360°-48°=312°

<h3>stay safe healthy and happy.</h3>

5 0

3 years ago

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Using the grid box, draw a net for a rectangular prism with a length of 8 units, width of 2 units and height of 3 units

prohojiy [21]

Answer: The answer is in the attached figure.

Step-by-step explanation: We are given to draw a net for a rectangular prism of length 8 units, width 2 units and height 3 units.

What is a rectangular prism? It is a a solid three-dimensional object consisting of six faces, where each of the face is a rectangle. The same cross-section along a length of a rectangular prism makes it a prism. We also call it as a cuboid.

As given in the question, a rectangular prism ABCDEFGH is drawn in the attached figure, where length is 8 units, width is 2 units and height is 3 units.

8 0

3 years ago

Consider F and C below. F(x, y, z) = yz i + xz j + (xy + 6z) k C is the line segment from (2, 0, −2) to (5, 4, 2) (a) Find a fun

WITCHER [35]

Answer:

Required solution (a) $f(x,y,z)=xyz+3z^2+C$ (b) 40.

Step-by-step explanation:

Given,

$F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k$

(a) Let,

$F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k=f_x \uvec{i} +f_y \uvex{j}+f_z\uvec{k}$

Then,

$f_x=yz,f_y=xz,f_z=xy+6z$

Integrating $f_x$ we get,

$f(x,y,z)=xyz+g(y,z)$

Differentiate this with respect to y we get,

$f_y=xz+g'(y,z)$

compairinfg with $f_y=xz$ of the given function we get,

$g'(y,z)=0\implies g(y,z)=0+h(z)\implies g(y,z)=h(z)$

Then,

$f(x,y,z)=xyz+h(z)$

Again differentiate with respect to z we get,

$f_z=xy+h'(z)=xy+6z$

on compairing we get,

$h'(z)=6z\implies h(z)=3z^2+C$ (By integrating h'(z)) where C is integration constant. Hence,

$f(x,y,z)=xyz+3z^2+C$

(b) Next, to find the itegration,

$\int_C \vec{F}.dr=\int_C \nabla f. d\vec{r}=f(5,4,2)-f(2,0,-2)=(52+C)-(12+C)=40$

3 0

3 years ago

A rocking horse has a weight limit of 60pounds. What percentage of the weight limit is 33 pounds? What percentage of the weight

bixtya [17]

Answer:

The percentage is 55% when weight limit is 33 pounds.

The percentage is 190% when weight limit is 114 pounds.

The 95% of the limit weighs 57 pounds.

Step-by-step explanation:

Given:

Weight limit of rocking horse = 60 pounds.

We need to find:

a) What percentage of the weight limit is 33 pounds.

b)What percentage of the weight limit is 114 pounds.

c) What weight is 95% of the limit.

Now Solving for a we get;

Weight limit = 33 pounds

Now percentage of the weight limit can be calculated by dividing given weight limit with total weight limit and then multiplying by 100 we get;

framing in equation form we get;

percentage of the weight limit = $\frac{33}{60}\times100 = 55\%$

Hence The percentage is 55% when weight limit is 33 pounds.

Now Solving for b we get;

Weight limit = 114 pounds

Now percentage of the weight limit can be calculated by dividing given weight limit with total weight limit and then multiplying by 100 we get;

framing in equation form we get;

percentage of the weight limit = $\frac{114}{60}\times100 = 190\%$

Hence The percentage is 190% when weight limit is 114 pounds.

Now Solving for c we get;

Percentage Weight = 95%

Now Amount of weight limit can be calculated by multiplying Percentage weight limit with total weight limit and then Dividing by 100 we get;

framing in equation form we get;

percentage of the weight limit = $\frac{95}{100}\times60 = 57 \pounds$

Hence The 95% of the limit weighs 57 pounds.

4 0

3 years ago

Chen buys 4 tickets to a soccer game. The total cost before taxes is $80. Which equation would you use to determine the price, p

Assoli18 [71]

Answer:

A. 4p=80

Step-by-step explanation:

Total Cost of 4 tickets=$80

Price=p

Quantity=4

Total cost=price×quantity

80=p×4

80=4p

80=4p is the equation that can be used to determine price

From the equation

80=4p

Divide both sides by 4

80/4=4p/4

20=p

Price is $20 per ticket

7 0

2 years ago

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