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3 years ago

Help anyone, would be nice!

Mathematics

1 answer:

grin007 [14]3 years ago

8 0

Answer:

Quadrant 2 has negative x and positive y

Quadrant 4 has negative y and positive x

Step-by-step explanation:

The in Quadrant 2

(-1,1)

(0,2) "I think that"

In Quadrant 4

(7,-10)

(2,-7)

(9,0)"also I think that"

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Estimated product of 2 1/2 x 2 1/3

tatyana61 [14]

The answer is 35/6. Hope you get it!

6 0

3 years ago

Select all of the ratios that are equivalent to 1:5

andrew-mc [135]

Answer:

2/10 and 6/30 and 8/40

Step-by-step explanation:

2/10 reduces to 1/5

6/30 reduces to 1/5

8/40 reduces to 1/5

4 0

3 years ago

Help me please and thank you

elixir [45]

Answer: 29.55°

Step-by-step explanation: Just subtract 44.25° from 73.80°. You should get

29.55°.

4 0

3 years ago

Read 2 more answers

Use the elimination method to solve the system of equations. Choose the correct ordered pair. 5x - 2y = 9 3x + 4y = - 5 O A. (5,

marta [7]

Answer:

Step-by-step explanation:

4(5x-2y=9)

-2(3x+4y=-5)

20-20x-8y=36

+6x-6x-8y=10

36-20x=10+6x-6x

36-36-20x-6x=10

-26x=10-36

-26x/-26=-26/-26

x=1

3 0

3 years ago

Find a matrix representation of the transformation L(x, y) = (3x + 4y, x − 2y).

mario62 [17]

Answer:

$\left[\begin{array}{cc}x&y\end{array}\right] * \left[\begin{array}{cc}3&1\\4&-2\end{array}\right] = \left[\begin{array}{cc}3x+4y&x-2y\end{array}\right]$

Step-by-step explanation:

The general matrix representation for this transformation would be:

$\left[\begin{array}{cc}x&y\end{array}\right] * A = \left[\begin{array}{cc}3x+4y&x-2y\end{array}\right]$

As the matrix A should have the same amount of rows as columns in the firs matrix and the same amount of columns as the result matrix it should be a 2x2 matrix.

$\left[\begin{array}{cc}x&y\end{array}\right] * \left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}3x+4y&x-2y\end{array}\right]$

Solving the matrix product you have that the members of the result matrix are:

3x+4y = a*x + c*y

x - 2y = b*x + d*y

So the matrix A should be:

$\left[\begin{array}{cc}3&1\\4&-2\end{array}\right]$

8 0

3 years ago