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ArbitrLikvidat [17]
2 years ago
11

Help anyone, would be nice!

Mathematics
1 answer:
grin007 [14]2 years ago
8 0

Answer:

Quadrant 2 has negative x and positive y

Quadrant 4 has negative y and positive x

Step-by-step explanation:

The in Quadrant 2

(-1,1)

(0,2) "I think that"

In Quadrant 4

(7,-10)

(2,-7)

(9,0)"also I think that"

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Uh can someone please help? please get it right and try to explain how
Anestetic [448]

Answer:

From least likely to most likely:

Colorado Bronze wins

I Am Pat wins

Good Legs Lance wins

Step-by-step explanation:

Converting all probabilities to the same type may be easier to visualize and see the chances. Let's convert each chance to percentage:

P(I Am Pat wins) = 3/10 = <u>30%</u>

P(Good Legs Lance wins) = 0.6 = <u>60%</u>

P(Colorado Bronze wins) = 10%= <u>10%</u>

Thus, the desired order is:

Colorado Bronze wins

I Am Pat wins

Good Legs Lance wins

4 0
3 years ago
Read 2 more answers
In a certain community, 30% of the families own a dog, and 20% of the families that own a dog also own a cat. It is also known t
Komok [63]

Answer:

What is the probability that a randomly selected family owns a cat? 34%

What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat? 82.4%

Step-by-step explanation: We can use a Venn (attached) diagram to describe this situation:

Imagine a community of 100 families (we can assum a number, because in the end, it does not matter)

So, 30% of the families own a dog = .30*100 = 30

20% of the families that own a dog also own a cat = 0.2*30 = 6

34% of all the families own a cat = 0.34*100 = 34

Dogs and cats: 6

Only dogs: 30 - 6 = 24

Only cats: 34 - 6 = 28

Not cat and dogs: 24+6+28 = 58; 100 - 58 = 42

What is the probability that a randomly selected family owns a cat?

34/100 = 34%

What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat?

A = doesn't own a dog

B = owns a cat

P(A|B) = P(A∩B)/P(B) = 28/34 = 82.4%

5 0
3 years ago
Read 2 more answers
Dana says that all even numbers are composite.<br><br> Is she correct?
Ksenya-84 [330]

Answer:

yes

Step-by-step explanation:

all even numbers greater than two are composite numbers

8 0
3 years ago
What is the problem of this solving?!
nika2105 [10]
     This question can be solved primarily by L'Hospital Rule and the Product Rule.

y= \lim_{x \to 0}  \frac{x^2cos(x)-sin^2(x)}{x^4}
 
     I) Product Rule and L'Hospital Rule:

y= \lim_{x \to 0} \frac{[2xcos(x)-x^2sin(x)]-2sin(x)cos(x)}{4x^3}
 
     II) Product Rule and L'Hospital Rule:

y= \lim_{x \to 0} \frac{[-2xsin(x)+2cos(x)]-[2xsin(x)+x^2cos(x)]-[2cos^2(x)-2sin^2(x)]}{12x^2} \\ y= \lim_{x \to 0} \frac{2cos(x)-4xsin(x)-x^2cos(x)-2cos^2(x)+2sin^2(x)}{12x^2}
 
     III) Product Rule and L'Hospital Rule:

]y= \alpha + \beta \\ \\ \alpha =\lim_{x \to 0} \frac{-2sin(x)-[4sin(x)+4xcos(x)]-[2xcos(x)-x^2sin(x)]}{24x} \\ \beta = \lim_{x \to 0} \frac{4sin(x)cos(x)+4sin(x)cos(x)}{24x} \\  \\ y = \lim_{x \to 0} \frac{-6sin(x)-4xcos(x)-2xcos(x)+x^2sin(x)+8sin(x)cos(x)}{24x}
 
     IV) Product Rule and L'Hospital Rule:

y = \phi + \varphi \\  \\ \phi = \lim_{x \to 0}  \frac{-6cos(x)-[-4xsin(x)+4cos(x)]-[2cos(x)-2xsin(x)]}{24x}  \\ \varphi = \lim_{x \to 0}  \frac{[2xsin(x)+x^2cos(x)]+[8cos^2(x)-8sin(x)]}{24x}
 
     V) Using the Definition of Limit:

y= \frac{-6*1-4*1-2*1+8*1^2}{24}  \\ y= \frac{-4}{24}  \\ \boxed {y= \frac{-1}{6} }
3 0
3 years ago
How do you compute term life insurance?
Lynna [10]

Answer:

Most insurance companies say a reasonable amount for life insurance is six to 10 times the amount of annual salary. Another way to calculate the amount of life insurance needed is to multiply your annual salary by the number of years left until retirement.

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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