Answer:
William was 0.5 points away from a perfect score.
Step-by-step explanation:
If the teacher didn't subtract 5 points, he would have 24.5 + 5 = 29.5 points.
30 - 29.5 = 0.5
William was 0.5 points away from a perfect score.
In getting the area of and equilateral triangle, you must first consider that all of its sides are congruent and that is 3 inches, so the formula in getting the area is height form its base so in getting its height you must use the pythagorean theorem by dividing the triangle so the hypotenuse of it is 3 and the base of 1.5inches, so the height is 4.77 inches then the area is 7.15 sqr.inch
X-y=6 Equation 1
x+y=4 Equation 2
To graph the given system of equation, first find x and y-intercept of each equation.
x-y=6
When y=0
x=6 Point is (6,0)
When x=0
-y=6
y=-6 Point is (0,-6)
Now x-intercept and y-intercept for equation 2.
x+y=4
When x=0
y=4 Point is (0,4)
When y=0
x=4 Point is (4,0)
Now plot these points on the graph, the lines intersect each other at point (5,-1), which is the solution of the given system.
Answer: (5,-1)
Answer:
is their any way I can get some more info on this problem
Step-by-step explanation:
Answer:
Step-by-step explanation:
The volume of the pyramid = (1/3)*area of base *height
= (1/3)*10*24*13 = 1040 cubic units.
The total surface area = area of rectangular base + area of 2 isosceles triangles with a base of 24 units + area of 2 isosceles triangles with a base of 10 units.
Area of rectangular base = 24*10 = 240 sq units.
The slant height of isosceles triangles with a base of 24 units = [(10/2)^2+13^2]^0.5 = [25+169]^0.5 = 194^0.5 = 13.92838828 units.
The area of 2 isosceles triangles with a base of 24 units 2*24*13.92838828/2 = 334.2813187 sq units.
The slant height of isosceles triangles with a base of 10 units = [(24/2)^2+13^2]^0.5 = [144+169]^0.5 = 194^0.5 = 17.69180601 units.
The area of 2 isosceles triangles with a base of 10 units 2*10*17.69180601/2 = 176.9180601 sq units.
The total surface area of the pyramid = 240 + 334.2813187 + 176.9180601 = 591.9731247 sq units.