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2 years ago

PLZ HELP HURRY PLZ!!!!!!!!!!!!!!!!

Mathematics

1 answer:

Mademuasel [1]2 years ago

4 0

Answer:

Step-by-step explanation:

You subtract the "-6" from the y, and you get +6 (which eliminates A and B). You subtract the "-2" from the x, and you get +2 (which eliminates C)

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Coordinates point a

Genrish500 [490]

I'm sorry cordinate what

6 0

3 years ago

98x24(100-2)x24 using the distributive property

boyakko [2]

Answer:

98 x 24 = 2352

2352 x 2400 = 5,644,800

2352 x (-48) = - 112,896

5,644,800 - 112,896 = 5,531,904

5,531,904 x 24 = 132,765,696

Step-by-step explanation:

8 0

3 years ago

Given the circle below secant kjI and tangent hi find the length of hi round to the nearest tenth if necessary.

garik1379 [7]

The length of the segment HI in the figure is 32.9

<h3>How to determine the length HI?</h3>

To do this, we make use of the following secant-tangent equation:

HI² = KI * JI

From the figure, we have:

KI = 21 + 24 = 45

JI = 24

So, we have:

HI² = 45 * 24

Evaluate the product

HI² = 1080

Take the square root of both sides

HI = 32.9

Hence, the length of the segment HI is 32.9

Read more about secant and tangent lines at:

brainly.com/question/14962681

#SPJ1

3 0

1 year ago

12% of children are nearsighted, but this condition often is not detected until they go to kindergarten. A school district tests

Klio2033 [76]

Answer:

There is a 34.60% probability that 0 or 1 of them is nearsighted.

Step-by-step explanation:

For each children, there are only two possible outcomes. Either they are nearsighted, or they are not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem, we have that:

12% of children are nearsighted. This means that $p = 0.12$ .

A school district tests all incoming kindergarteners' vision. In a class of 18 kindergarten students, what is the probability that 0 or 1 of them is nearsighted?

There are 18 students, so $n = 18$

This probability is:

$P = P(X = 0) + P(X = 1)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{18,0}.(0.12)^{0}.(0.88)^{18} = 0.1002$

$P(X = 1) = C_{18,1}.(0.12)^{1}.(0.88)^{17} = 0.2458$

$P = P(X = 0) + P(X = 1) = 0.1002 + 0.2458 = 0.3460$

There is a 34.60% probability that 0 or 1 of them is nearsighted.

5 0

3 years ago

If <img src="https://tex.z-dn.net/?f=tan%20%28x%29%20%3D%20%5Cfrac%7B5%7D%7B12%7D" id="TexFormula1" title="tan (x) = \frac{5}{12

Alekssandra [29.7K]

Explanation:

First, we need to find the values of the sine and cosine of x knowing the value of tan x and x being in the 3rd quadrant. Since tan x = 5/12, using Pythagorean theorem, we know that

$\sin x = -\frac{5}{13}\;\;\text{and}\;\;\cos x = -\frac{12}{13}$