The value of P(4, 6) when the two number cubes are tossed is 1/36
<h3>How to determine the probability?</h3>
On each number cube, we have:
Sample space = {1, 2, 3, 4, 5, 6}
The individual probabilities are then represented as:
P(4) =1/6
P(6) =1/6
The value of P(4, 6) when the two number cubes are tossed is:
P(4, 6) = P(4) * P(6)
This gives
P(4, 6) = 1/6 * 1/6
Evaluate
P(4, 6) = 1/36
Hence, the value of P(4, 6) when the two number cubes are tossed is 1/36
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Answer:
It's a negative 4 and the variable n and can be used for anything or any equation.
Yes because the gap is one less than the bigger of the two integers, plus you are adding a little bit more to the bigger integer so the sum will always be bigger than the difference.
Answer:
135
Step-by-step explanation:
(7+3)^2 + (8-1) * 5
Parentheses first
(10)^2 + (7) * 5
Exponents next
100 + 7*5
Multiply
100 + 35
Add
135
Answer:
can you comment the real question because this is just gibrish
Step-by-step explanation:
