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3 years ago

A-3=15 compare and contrast

Mathematics

2 answers:

sveticcg [70]3 years ago

8 0

A = 18 but what should we compare.

melisa1 [442]3 years ago

4 0

A=18 but idk what you mean by compare and contrast

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What is the element a^23 in matrix A? <br> A=8 -4 -3<br> 3 -9 -5<br> -8 8 8

labwork [276]

8 -4 -3
3 -9 -5-8 8 8

This is a matrix of 3 rows and 3 columns (it's called square matrix because the number of rows = the number of columns)

To localise an element of a matrix we use indices R and C, the first index being ALWAYS the row and the second, ALWAYS the column.

Hence:
A₂₃ = the element in row 2 and column 3, that is - 5

COLUMN
1st 2nd 3rd
--------------------------------
1st | 8 -4 -3
ROW 2nd | 3 -9 -5 3rd |-8 8 8

4 0

3 years ago

Read 2 more answers

I’ll give brainliest if u give me answer and explanation (picture attached)

Marat540 [252]

Answer:

m<2=133°

Step-by-step explanation:

180-47=133

Hope this helps! :)

7 0

3 years ago

Read 2 more answers

Help please! I don’t get the question

Vlad [161]

Option B:

$9^{\frac{1}{8}x}$ is the equivalent expression to the given expression.

Solution:

Given expression:

$$\sqrt[4]{9} ^{\frac{1}{2}x}$

To find the equivalent expression to the given expression.

$$\sqrt[4]{9} ^{\frac{1}{2}x}$

Using radical rule: $$\sqrt[n]{a}=a^{\frac{1}{n}}$

So that $$\sqrt[4]{9} = 9^{\frac{1}{4} }$ .

$$\sqrt[4]{9} ^{\frac{1}{2}x}=\left(9^{\frac{1}{4}}\right)^{\frac{1}{2} x}$

Using exponent rule: $\left(a^{b}\right)^{c}=a^{b c}$

$=9^{\frac{1}{4} \cdot \frac{1}{2} x}$

$=9^{\frac{1}{8}x}$

$$\sqrt[4]{9} ^{\frac{1}{2}x}=9^{\frac{1}{8}x}$

Hence $9^{\frac{1}{8}x}$ is the equivalent expression to the given expression.

Option B is the correct answer.

8 0

3 years ago

What is proportional

AnnyKZ [126]

Answer: Proportional is two varying quantities are said to be in a relation of proportionality, if they are multiplicatively connected to a constant, that is, when either their ratio or their product yields a constant. The value of this constant is called the coefficient of proportionality or proportionality constant.

8 0

3 years ago

Apply Gaussian quadrature with n = 4 to approximate integrate sin x^2dx from 1 to 5

maks197457 [2]

First, recall that Gaussian quadrature is based around integrating a function over the interval [-1,1], so transform the function argument accordingly to change the integral over [1,5] to an equivalent one over [-1,1].

$x=2t+3\iff t=\dfrac x2-\dfrac32\implies2\mathrm dt=\mathrm dx$
$x=1\implies t=\dfrac{2-6}4=-1$
$x=5\implies t=\dfrac{10-6}4=1$

So,

$\displaystyle\int_{x=1}^{x=5}\sin x^2\,\mathrm dx=\displaystyle2\int_{t=-1}^{t=1}\sin(2t+3)^2\,\mathrm dt$

Let $f(t)=2\sin(2t+3)^2$ . With $n=4$ , we're looking for coefficients $c_i$ and nodes $x_i$ , with $1\le i\le4$ , such that

$\displaystyle\int_{-1}^1f(t)\,\mathrm dt\approx c_1f(x_1)+\cdots+c_4f(x_4)$

You can either try solving for each with the help of a calculator, or look up the values of the weights and nodes (they're extensively tabulated, and I'll include a link to one such reference).

Using the quadrature, we then have

$\displaystyle\int_{-1}^1f(t)\,\mathrm dt\approx0.3749f(-0.8611)+0.6521f(-0.3400)+0.6521f(0.3400)+0.3749f-0.8611)$
$\displaystyle\int_{-1}^1f(t)\,\mathrm dt\approx0.5790$

4 0

3 years ago