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3 years ago

Whats the area of this? Im lost...

Mathematics

1 answer:

Vlad1618 [11]3 years ago

8 0

Add the b1 with b2, which is 26. Then, multiply it by the height, which is 9. 26x9=234. Then, divide it by 2, which would result in 117. just turn it 90 degrees and u will see a trapezoid.

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Explain how you can find 4 x 754 using two different methods

Citrus2011 [14]

Solution: The value of $4\times 754$ is 3,016.

Explanation:

The first method of multiplication is given below:

Multiply the ones digit by the multiplier and write the ones digit of the result in the bottom line and add the tens digit to the next resultant, and same happens with the next number multiplied. This method show in given figure.

The second method of multiplication is given below:

Write the digits as the addition of their place values and then multiply those place value by multiplier individually after that add the results.

$4\times 754=4\times (700+50+4)\\4\times 754=4\times700+4\times50+4\times4\\4\times754=2800+200+16\\4\times754=3016$

Therefore, the value of $4\times 754$ is 3,016.

6 0

3 years ago

Read 2 more answers

What’s the word problem... solve it... need help with 7 please! Thanks you

nekit [7.7K]

30. you can model this with an equation and solve, x being the smallest number and the x+1 and x+2 representing the consecutive numbers.

x+(x+1)+(x+2)=93
3x+3=93
3x=90
x=30
x+1=31
x+2=32
30+31+32=93

4 0

3 years ago

Need help Thank you very much

Brrunno [24]

Answer:

A is right I believe

Step-by-step explanation:

a: 5x

b: 2x

c: 1/5x

d: 1/2x

4 0

3 years ago

The profile of the cables on a suspension bridge may be modeled by a parabola. The central span of the bridge is 1210 m long and

brilliants [131]

Answer:

The approximated length of the cables that stretch between the tops of the two towers is 1245.25 meters.

Step-by-step explanation:

The equation of the parabola is:

$y=0.00035x^{2}$

Compute the first order derivative of y as follows:

$y=0.00035x^{2}$

$\frac{\text{d}y}{\text{dx}}=\frac{\text{d}}{\text{dx}}[0.00035x^{2}]$

$=2\cdot 0.00035x\\\\=0.0007x$

Now, it is provided that |x | ≤ 605.

⇒ -605 ≤ x ≤ 605

Compute the arc length as follows:

$\text{Arc Length}=\int\limits^{x}_{-x} {1+(\frac{\text{dy}}{\text{dx}})^{2}} \, dx$

$=\int\limits^{605}_{-605} {\sqrt{1+(0.0007x)^{2}}} \, dx \\\\={\displaystyle\int\limits^{605}_{-605}}\sqrt{\dfrac{49x^2}{100000000}+1}\,\mathrm{d}x\\\\={\dfrac{1}{10000}}}{\displaystyle\int\limits^{605}_{-605}}\sqrt{49x^2+100000000}\,\mathrm{d}x\\\\$

Now, let

$x=\dfrac{10000\tan\left(u\right)}{7}\\\\\Rightarrow u=\arctan\left(\dfrac{7x}{10000}\right)\\\\\Rightarrow \mathrm{d}x=\dfrac{10000\sec^2\left(u\right)}{7}\,\mathrm{d}u$

$\int dx={\displaystyle\int\limits}\dfrac{10000\sec^2\left(u\right)\sqrt{100000000\tan^2\left(u\right)+100000000}}{7}\,\mathrm{d}u$

$={\dfrac{100000000}{7}}}{\displaystyle\int}\sec^3\left(u\right)\,\mathrm{d}u\\\\=\dfrac{50000000\ln\left(\tan\left(u\right)+\sec\left(u\right)\right)}{7}+\dfrac{50000000\sec\left(u\right)\tan\left(u\right)}{7}\\\\=\dfrac{50000000\ln\left(\sqrt{\frac{49x^2}{100000000}+1}+\frac{7x}{10000}\right)}{7}+5000x\sqrt{\dfrac{49x^2}{100000000}+1}$

Plug in the solved integrals in Arc Length and solve as follows:

$\text{Arc Length}=\dfrac{5000\ln\left(\sqrt{\frac{49x^2}{100000000}+1}+\frac{7x}{10000}\right)}{7}+\dfrac{x\sqrt{\frac{49x^2}{100000000}+1}}{2}|_{limits^{605}_{-605}}\\\\$

$=1245.253707795227\\\\\approx 1245.25$

Thus, the approximated length of the cables that stretch between the tops of the two towers is 1245.25 meters.

7 0

3 years ago

List the elements in the set. 1) {x 1 x is an integer between -7 and -3}

omeli [17]

Answer:

सामाजिक अध्ययन र जिवनोपयोगी शिक्षाको महत्व दसांउनुहोस

8 0

2 years ago