What is the area, in square cm, of a rectangle with a length of 5.6 cm and a width of 6 cm? *

Mathematics

2 answers:

Blizzard [7]2 years ago

7 0

Answer:

33.6 cm²

Step-by-step explanation:

Length x width = Area of the rectangle

5.6cm x 6cm = 33.6m²

julsineya [31]2 years ago

6 0

Answer:

I think its 30.36

Step-by-step explanation:

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Sketch the line passing through the pair of points and identify the line as having a positive slope, a negative slope, a zero sl

scoundrel [369]

Answer:

line will be horizontal running through (0,2)

Step-by-step explanation:

6,2
1,2
2-2/1-6 = 0/-5 = 0 slope. 2 = 0x6+b, 2=b. line will be y=b , y=2.

5 0

2 years ago

Type the correct answer in each box. If necessary, round your answers to the nearest hundredth.

disa [49]

Answer:

Perimeter = 32.44 units

Area = 30 square units

Step-by-step explanation:

Given

Vertices

A(2,8), B(16,2) and C(6,2)

WE have to determine the lengths of all sides before finding the perimeter and area.

The formula of modulus is:

$d = \sqrt{(x_{2}- x_{1})^{2} +(y_{2}-y_{1})^{2}}\\AB=\sqrt{(16-2)^{2} +(2-8)^{2}}\\=\sqrt{(14)^{2} +(-6)^{2}}\\=\sqrt{196+36}\\ =\sqrt{232}\\=15.23\\\\BC=\sqrt{(6-16)^{2} +(2-2)^{2}}\\=\sqrt{(-10)^{2} +(0)^{2}}\\=\sqrt{100+0}\\ =\sqrt{100}\\=10\\\\AC=\sqrt{(6-2)^{2} +(2-8)^{2}}\\=\sqrt{(4)^{2} +(-6)^{2}}\\=\sqrt{16+36}\\ =\sqrt{52}\\=7.21\\\\$

So the perimeter is:

$Perimeter=AB+BC+AC\\=15.23+10+7.21\\=32.44\ units$

Using hero's formula,

$s=\frac{perimeter}{2}\\s=\frac{32.44}{2}\\ s=16.22\\Area=\sqrt{s(s-a)(s-b)(s-c)}\\=\sqrt{16.22(16.22-15.23)(16.22-10)(16.22-7.21)}\\=\sqrt{(16.22)(0.99)(6.22)(9.01)}\\=\sqrt{899.91}\\=29.99\ square\ units$