1 joule = 6,242e+18ev
20 joule = 20 joule *6,242e+18 ev/joule =1,248e+20 ev
1,248e+20 ev / (10 ev / photon) =1,248e+19 photons.
(2^8 *3^-5* 6^0)^-2 * ((3^-2)/(2^3))^4 * 2^28
anything to the 0 power is 1
(2^8 *3^-5* 1)^-2 * ((3^-2)/(2^3))^4 * 2^28
using the power of power property to take the power inside
(2^(8*-2) *3^(-5* -2) * (3^-2*4)/(2^3*4) * 2^28
simplify
2^ -16 * 3^10 * 3^-8 /2*12 * 2^28
get rid of the division by making the exponent negative
2^-16 * 3^10 * 3^-8 *2*-12 * 2^28
combine exponents with like bases
2^(-16-12+28) * 3^(10-8)
2^(0) *3^2
anything to the 0 power is 1
1*9
9
This would be 2(6)^4 + 5*6
= 2592 + 30
= 2622 Answer
Answer:
6(3x-1)
Step-by-step explanation:
They both have a common factor of 6
So divide 6 and take it out to give:
6(3x-1)
(3x^5 + 8x^3) - (7x^2 - 6x^3) = 3x^5 + 8x^3 - 7x^2 - 6x^3 = 3x^5 + 2x^3 - 7x^2
