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klasskru [66]
3 years ago
10

Simplify the following expression. 12a + 2a

Mathematics
2 answers:
Elanso [62]3 years ago
8 0

Answer:

14a

Step-by-step explanation:

mamaluj [8]3 years ago
6 0

Answer:

14a

Step-by-step explanation:

Combining like-terms gives us 12a+2a=14a

Hope this helped!

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Angles STU and UTV combine to form right angle STV. Which expression could be used to find the measure,in degrees,of angle UTV?
Sergeu [11.5K]
STV=STU+UTV

But,
STV=90° and STU = 75°

Therefore,
90=75+UTV => UTV = 90-75

Therefore, expression A is the one that can be used to find UTV.
8 0
3 years ago
The layer of gold coating on a ring should be 0.03 millimeters thick when the ring is completed. A coating of 0.021 millimeters
Arisa [49]
The amount of gold coating in millimeters needed for the ring is the difference between the total coating and the coating that has already been applied. From the given above, that would be,
                                    0.03 mm - 0.021 mm = 0.009 mm
Thus, the answer to this question is letter B. 
6 0
4 years ago
Read 2 more answers
What is 5.5 written as a fraction in simplest form
julia-pushkina [17]
5.5 as a fraction is 11/2
6 0
3 years ago
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A particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past
Vadim26 [7]

Answer:

We conclude that deluxe tire averages less than 50,000 miles before it needs to be replaced which means that the claim is not supported.

Step-by-step explanation:

We are given that a particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past studies of this tire, the standard deviation is known to be 8000.

From the 28 tires surveyed, the mean lifespan was 46,500 miles with a standard deviation of 9800 miles.

<u><em>Let </em></u>\mu<u><em> = average miles for deluxe tires</em></u>

So, Null Hypothesis, H_0 : \mu \geq 50,000 miles   {means that deluxe tire averages at least 50,000 miles before it needs to be replaced}

Alternate Hypothesis, H_A : \mu < 50,000 miles    {means that deluxe tire averages less than 50,000 miles before it needs to be replaced}

The test statistics that will be used here is <u>One-sample z test statistics</u> as we know about population standard deviation;

                                  T.S.  = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean lifespan = 46,500 miles

            \sigma = population standard deviation = 8000 miles

            n = sample of tires = 28

So, <u><em>test statistics</em></u>  =  \frac{46,500-50,000}{\frac{8000}{\sqrt{28} } }

                               =  -2.315

The value of the test statistics is -2.315.

Now at 5% significance level, the z table gives critical value of -1.6449 for left-tailed test. Since our test statistics is less than the critical value of z as -2.315 < -1.6449, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that deluxe tire averages less than 50,000 miles before it needs to be replaced which means that the claim is not supported.

4 0
3 years ago
Please, can someone help?
LekaFEV [45]
The area of that figure is 2453.25 square feet

First, you would need to find the area of the rectangle

(L)(W)
(70)(30)
2100

Then since it is only a semi circle, the formula is pi*r^2/2

You find the area of a full circle first

(3.14)(15^2)
(3.14)(225)
706.5

Then you divide that by 2 since it’s only half a circle

706.5/2 = 353.25

Finally you add that by the area of the rectangle

2100 + 353.25 = 2453.25 square feet
3 0
4 years ago
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