23. The answer is B) x-6.
23.) The answer is D) x + 3
Answer:
0.1333 = 13.33% probability that bridge B was used.
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is

In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Arrives home by 6 pm
Event B: Bridge B used.
Probability of arriving home by 6 pm:
75% of 1/3(Bridge A)
60% of 1/6(Bridge B)
80% of 1/2(Bridge C)
So

Probability of arriving home by 6 pm using Bridge B:
60% of 1/6. So

Find the probability that bridge B was used.

0.1333 = 13.33% probability that bridge B was used.
-4(3-x)+6=2(x-3)
-12+4x+6=2x-6
-6+4x=2x-6
-6+6=2x-4x
0=-2x
0/x=-2
One way is to turn them into fractions and simplify them then see if they are equal exg
8:4 and 6:3
turn into fractions
8/4 and 6/3
2/1 and 2/1
equal