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grigory [225]
2 years ago
8

The base diameter and the height of a cone are both

Mathematics
1 answer:
WITCHER [35]2 years ago
3 0

Answer:

11/ 42. *. X^ 2. * X = I/3 X A * h; if E = 1/3 A

Then the answer is EX

Step-by-step explanation:

Volume of cone= 1/3 * base area * height

= 1/3 * pi* (X/2)^2 * X

= 1/3. * 22/ 7 * X^3/4

= 22/ 21 * X^3 / 4

= 11/21 *. X^2/ 2. *. X

= 11/ 42. * X^3

= 11/ 42. *. X^ 2. * X

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Sorry there is a few pics please help
Sever21 [200]

Answer:

D

Step-by-step explanation:

In the graph, there are only two values for a graph. In this case, those two values are crackers and calories.

7 0
3 years ago
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The length of a rectangle is equal to three times it’s widt. If the perimeter is equal to 96 feet, what is the length of the rec
exis [7]

Answer:

12 feet

Step-by-step explanation:

If we use a rectangle. there would be 4 sides the length we can represent as x and the width would result as 3x. If we use the perimeter formula, we would get 8x. 8x would equal 96, the perimeter.

8x= 96

x= 12

The length would be 12

Hope this helped!! :D

4 0
3 years ago
Due today please help<br><br>And also explain​
Lilit [14]
9) 24 pounds = 10.89 kilograms

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3 years ago
Read 2 more answers
Squared root 50 x squared root 8<br><br> surds
frez [133]

Answer:

20

Step-by-step explanation:

using the rule of radicals

\sqrt{a} × \sqrt{b} = \sqrt{ab} , then

\sqrt{50} × \sqrt{8}

= \sqrt{50(8)}

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6 0
1 year ago
Can I please get some help with this
Marizza181 [45]

After solving \sqrt[5]{128x^8y^2} we get 2x\sqrt[5]{4}\sqrt[5]{x^3}\sqrt[5]{y^2}

Step-by-step explanation:

We need to solve \sqrt[5]{128x^8y^2}

Applying the rule: \sqrt[a]{xy}=\sqrt[a]{x}.\sqrt[a]{y}

\sqrt[5]{128x^8y^2}\\=\sqrt[5]{128}\sqrt[5]{x^8}\sqrt[5]{y^2}\\We\,\,know\,\,that\,\,128=2\times2\times2\times2\times2\times2\times2=2^7\,\,or\,\,2^5.2^2\\=\sqrt[5]{2^5.2^2}\sqrt[5]{x^5.x^3}\sqrt[5]{y^2}\\=(2^5)^{\frac{1}{5}}\sqrt[5]{2^2}\sqrt[5]{x^5}\sqrt[5]{x^3}\sqrt[5]{y^2}\\=2x\sqrt[5]{4}\sqrt[5]{x^3}\sqrt[5]{y^2}

So, After solving \sqrt[5]{128x^8y^2} we get 2x\sqrt[5]{4}\sqrt[5]{x^3}\sqrt[5]{y^2}

Keywords: Solving with Exponents

Learn more about Solving with Exponents at:

  • brainly.com/question/4934417
  • brainly.com/question/13174254
  • brainly.com/question/13174255

#learnwithBrainly

3 0
3 years ago
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