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4 years ago

Simplify. give your answer in lowest terms.

Mathematics

2 answers:

tamaranim1 [39]4 years ago

8 0

The one in the title is different than the picture so I'm going to solve the picture and hope that is what you are looking for.

First we must find the least common multiple of 2 and 4. It is 4.

To get the denominator of the first term, 1/2, to be 4 we must mulitply both top and bottom by 2.

(1/2)(2/2) = 2/4

The number 2 is the same as the fraction 2/1. To get it to have the denominator of 4, we multiply both top and bottom by 4

(2/1)(4/4) = 8/4

Now we solve.

2/4 - 3/4 + 1/4 + 8/4

2/4 + 1/4 - 3/4 + 8/4

3/4 - 3/4 + 8/4

0 + 8/4

8/4 = 2

The answer is 2

(2 - 3 + 1 + 8) / 4

(- 1 + 1 + 8) / 4

(0 + 8) / 4

8 / 4

The answer is 2

nataly862011 [7]4 years ago

4 0

This is the answer simplified into the most specific terms

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3 years ago

Cylinder A has radius r and height h as shown in the diagram. Cylinder B has radius 4r and height 4h. How many times greater is

svetlana [45]

Answer:

The surface area of Cylinder B is 16 times the surface area of Cylinder A

Step-by-step explanation:

<u>Note</u>: <em>It is assumed we are looking at the total surface area (but the answer would be same for both cases)</em>

<h3>Given</h3>

Cylinders A with radius - r, height - h,
Cylinder B with radius - 4r, height - 4h.

The ratio of total surface areas of cylinder B to A

<h3>Solution</h3>

Total surface area of cylinder A is:

$S_A = 2\pi r(h + r)$

Total surface area of cylinder B is:

$S_B = 2\pi(4r)(4r + 4h) = 8\pi(4)(r + h) = 32\pi(r + h)$

Find the ratio of areas:

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2 years ago

First person to correctly answer will get brainliest

PtichkaEL [24]

Answer:

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Step-by-step explanation:

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3 years ago

What is the volume in cubic units?

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Answer:

60cm3

Step-by-step explanation:

Your base has 4

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3 years ago

Read 2 more answers

Find the equation of the line tangent to y = -3x2 + x - 5 at x = -1

SVEN [57.7K]

$\boxed{y+9=7(x+1)}$

<h2>Explanation:</h2>

The Point-Slope form of the equation of a line is given by:

$y-y_{0}=m(x-x_{0}) \\ \\ \\ Where: \\ \\ m:Slope \\ \\ (x_{0},y_{0}):A \ point$

To find the equation of the line tangent to $y=-3x^2+x-5 \ at \ x=-1$ , we need to take the derivative:

$\frac{dy}{dx}=-6x+ 1$

The slope of the line tangent to $y=-3x^2+x-5$ at $x=-1$ can be found evaluationg $x=1$ in the derivative:

$\frac{dy}{dx}\Bigr\rvert_{x=-1}=-6x+ 1 \\ \\ \\ \frac{dy}{dx}\Bigr\rvert_{x=-1}=-6(-1)+ 1 \\ \\ \\ m=\frac{dy}{dx}\Bigr\rvert_{x=-1}=7$

Finding the point:

$x_{0}=-1 \\ \\ Then: \\ \\ y_{0}=-3(-1)^2-1-5=-9 \\ \\ (x_{0},y_{0})=(-1,-9)$

Finally, our line is:

$y-(-9)=7(x-(-1)) \\ \\ \boxed{y+9=7(x+1)}$

The representation of this problem is shown below.

<h2>Learn more:</h2>

Derivative of functions: brainly.com/question/2142425

#LearnWithBrainly

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3 years ago