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2 years ago

7

In the expression ax+bx,a is a decimal and b is a fraction. How do you decide whether to write a as a fraction or b as a decimal

?

1 answer:

mezya [45]2 years ago

7 0

Answer:

f(x) = x^2 - x - 12

Step-by-step explanation:

The function is f(x) = (x + 3)(x - 4), or f(x) = x^2 - x - 12. Here, a = 1, b = -1, and c = -12.

HOPE THIS HELPED ;3

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What is the answer > , <, or = -37/8______-4.63

Lunna [17]

-37/8 as a decimal is -4.625. So: -4.62 > -4.63

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2 years ago

The function h(t) = 150 – 9t represents the height of a ball dropped from 150 feet after t seconds. What will the height of the

Alekssandra [29.7K]

After 1.4 seconds, t = 1.4.
h(t) = 150 - 9(1.4)
Multiply 9 by 1.4 to get 12.6.
h(t) = 150 - 12.6
Subtract 12.6 from 150 to get 137.4.
h(t) = 137.4.
The height of the ball would be 137.4 after 1.4 seconds.
Hope this helps!

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2 years ago

What is - 3/4 x (- 2/7) x 4/3? Explain your work

Naya [18.7K]

Hope this helped! the answer is 2^7

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2 years ago

The following data give the prices of seven textbooks randomly selected from a university bookstore.

swat32

Answer:

a) Mean = $121

Sum of deviations = $0

b) Standard deviation = 41.19

Variance = 1696.67

Range = $120

Step-by-step explanation:

We are given the following data:

$91 , $176 , $108 , $115 , $56 , $157 , $144

a) Mean and sum of deviations

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{847}{7} = 121$

Sum of deviations =

-30 + 55 - 13 - 6 - 65 + 36 + 23 = 0

The sum of deviations is zero dollars.

b) range, variance, and standard deviation

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

Sum of square of differences =

900 + 3025 + 169 + 36 + 4225 + 1296 + 529 = 10180

$\sigma = \sqrt{\dfrac{10180}{6}} = 41.19\\\\\sigma^2 = 1696.67$

Sorted data: 56, 91, 108, 115, 144, 157, 176

Range = Maximum - Minimum

Range = 176 - 56 = 120

5 0

2 years ago

I don't really know on this one. I'm thinking it's because if T kept going it would go into a 3rd quadrant but I'm not too sure.

enyata [817]

That is correct since the line in T is not straight it would eventually hit the third quadrant
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2 years ago