Answer:
Step-by-step explanation:
Here's how you convert:
![\sqrt[n]{x^m}=x^{\frac{m}{n}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5Em%7D%3Dx%5E%7B%5Cfrac%7Bm%7D%7Bn%7D)
The little number outside the radical, called the index, serves as the denominator in the rational power, and the power on the x inside the radical serves as the numerator in the rational power on the x.
A couple of examples:
![\sqrt[3]{x^4}=x^{\frac{4}{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E4%7D%3Dx%5E%7B%5Cfrac%7B4%7D%7B3%7D)
![\sqrt[5]{x^7}=x^{\frac{7}{5}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%5E7%7D%3Dx%5E%7B%5Cfrac%7B7%7D%7B5%7D)
It's that simple. For your problem in particular:
![\sqrt[3]{7}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B7%7D)
is the exact same thing as ![\sqrt[3]{7^1}=7^{\frac{1}{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B7%5E1%7D%3D7%5E%7B%5Cfrac%7B1%7D%7B3%7D)
Answer:
<u>After (3/2) months Tyler's gym would be a better deal.</u>
Step-by-step explanation:
Let x the number of months
Cody's Gym charges a $15 fee to join and $30 per month
y₁= 15 + 30x (1)
Tyler's Gym charges a $30 fee to join and $20 per month
y₂ = 15 + 30x (2)
See the attached figure which represent the graph of y₁ (with blue color) and y₂ (with red color)
The point of intersection between y₁ and y₂ is ( 3/2 , 60)
After 3/2 months Tyler's Gym charges will be less than Cody's Gym charges
So, the inequality will be:
<u>After (3/2) months Tyler's gym would be a better deal.</u>
So heterozygous means one dominant trait and one recessive trait (Ll). Homozygous is either 2 recessive traits or 2 dominat. (in this case ll).
1.)Genotype: Ll and ll
Phenotype: 50% chance of Long pea plant, 50% chance of short.
2.) Genotype: Ww (widows peak) and ww (no widows peak)
Phenotypes: 75% chance of widows peak and 25% of no widows peak.
3.) Genotype: BB and Bb
Phenotype: 100% chance of black
Well metric unit is for measurement and place value units is for numbers
Answer:
86 cm²
Step-by-step explanation:
Ok, so since 4 circles fit in the square, each circle's diameter must be 10.
Which means the radius of each circle is 5 because 10 ÷ 2 = 5.
Now we can solve for area.
A = πr²
A = 3.14 x 5²
A = 3.14 x 25
A = 78.5 cm²
78.5 cm² is the area of one circle so we multiply that by 4.
78.5 x 4 = 314 cm²
Now we subtract from the area of the square.
20 x 20 = 400 cm²
400 - 314 = 86 cm²
