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artcher [175]
3 years ago
8

Evaluate f(x)=1/4x for x=-5

Mathematics
1 answer:
Alexus [3.1K]3 years ago
4 0

Answer:

option 2. -1 1/4

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Functions
  • Function Notation

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

f(x) = 1/4x

<u>Step 2: Evaluate</u>

  1. Substitute in <em>x</em> [Function f(x)]:                                                                           f(-5) = 1/4(-5)
  2. Multiply:                                                                                                             f(-5) = -5/4
  3. Simplify:                                                                                                             f(-5) = -1 1/4
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3 years ago
I need help with this problem
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Answer:

65.56°

Step-by-step explanation:

We know that if we take dot product of two vectors then it is equal to the product of magnitudes of the vectors and cosine of the angle between them

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So, p·q=|p|*|q|*cosA

⇒cosA=\frac{u.v}{|u||v|}

Given u=-8i-3j and v=-8i+8j

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let A be angle before u and v

therefore, cosA=\frac{u.v}{|u||v|}=\frac{(-8)*(-8)+(-3)*(8)}{8.544*11.3137} =\frac{40}{96.664}

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5 0
3 years ago
The number of bacteria growing in an incubation culture increases with time according to n left parenthesis t right parenthesis
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 t = log5 (60000/2400)
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2 years ago
Read 2 more answers
Solve for x: 3/3x + 1/x+4 = 10/7x
Mekhanik [1.2K]
Given,

3/3x + 1/(x + 4) = 10/7x

1/x + 1/(x+4) = 10/7x

Because the first term on LHS has 'x' in the denominator and the second term in the LHS has '(x + 4)' in the denominator. So to get a common denominator, multiply and divide the first term with '(x + 4)' and the second term with 'x' as shown below

{(1/x)(x + 4)/(x + 4)} + {(1/(x + 4))(x/x)} = 10/7x

{(1(x + 4))/(x(x + 4))} + {(1x)/(x(x + 4))} = 10/7x

Now the common denominator for both terms is (x(x + 4)); so combining the numerators, we get,

{1(x + 4) + 1x} / {x(x + 4)} = 10/7x

(x + 4 + 1x) / (x(x + 4)) = 10/7x

(2x + 4) / (x(x + 4)) = 10/7x

In order to have the same denominator for both LHS and RHS, multiply and divide the LHS by '7' and the RHS by '(x + 4)'

{(2x+4) / (x(x + 4))} (7 / 7) = (10 / 7x) {(x + 4) / (x + 4)}

(14x + 28) / (7x(x + 4)) = (10x + 40) / (7x(x + 4))

Now both LHS and RHS have the same denominator. These can be cancelled. 

∴14x + 28 = 10x + 40
14x - 10x = 40 - 28
4x = 12
x = 12/4

∴x = 3



8 0
3 years ago
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