Answer:
The answer is option 3.
Step-by-step explanation:
First we have to find the area of both rectangle and triangle :
Rectangle,

Let base = 9,
Let height = 3,

Triangle,

Let base = 3,
Let height = 3,

Lastly, in order to find the shaded region you have to substract the area of triangle from the area of rectangle :

9514 1404 393
Answer:
Step-by-step explanation:
The form of the equation you are given is called "point-slope" form. The "slope" in this case is the per-hour fee. The point is (9 h, $195). Point-slope form generally looks like this:
y -k = m(x -h) . . . . . line with slope m through point (h, k)
Here, you have m=15, (h, k) = (9, 195), so the equation looks like ...
y -195 = 15(x -9)
__
The "one-time fee" is the cost when hours are zero.
y -195 = 15(0 -9)
y = 195 -9(15) = 60 . . . . add 195 to both sides, and evaluate
The one-time fee is $60.
Answer:
Step-by-step explanation:
It is given that, 
We need to find the value of 
As 
Solving LHS

Now comparing the coefficients of 
In LHS the coefficient of
is 25
In RHS the coefficient of
is 
It implies that, 
So, the value of
is 25.