<u>Hope this helped!</u>
<u>First Row</u>
6
5
(this one is already done)
<u>Second Row</u>
4
5
6
11
Complete question:
The growth of a city is described by the population function p(t) = P0e^kt where P0 is the initial population of the city, t is the time in years, and k is a constant. If the population of the city atis 19,000 and the population of the city atis 23,000, which is the nearest approximation to the population of the city at
Answer:
27,800
Step-by-step explanation:
We need to obtain the initial population(P0) and constant value (k)
Population function : p(t) = P0e^kt
At t = 0, population = 19,000
19,000 = P0e^(k*0)
19,000 = P0 * e^0
19000 = P0 * 1
19000 = P0
Hence, initial population = 19,000
At t = 3; population = 23,000
23,000 = 19000e^(k*3)
23000 = 19000 * e^3k
e^3k = 23000/ 19000
e^3k = 1.2105263
Take the ln
3k = ln(1.2105263)
k = 0.1910552 / 3
k = 0.0636850
At t = 6
p(t) = P0e^kt
p(6) = 19000 * e^(0.0636850 * 6)
P(6) = 19000 * e^0.3821104
P(6) = 19000 * 1.4653739
P(6) = 27842.104
27,800 ( nearest whole number)
Using BEDMAS you follow the structure of what processes you need to do in the right mathematical order.
In this case, Brackets first, multiplication second, then adding.
Therefore answer he answer is C 184
So we will be using 
form, in which m = slope and b = y-intercept. Since we know the slope (-8), all we need to do is solve for the y-intercept. We can do this by inserting (-2,2) into the equation and solve for b.
Firstly, do the multiplication: 
Next, subtract 16 on both sides, and your answer will be -14 = b
Using the previous info we have, our equation is y = -8x - 14
