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eduard
3 years ago
5

PLEASEEE HELP DUE SOON!

Mathematics
2 answers:
Art [367]3 years ago
7 0
Y-coordinates are same so you just need to find distance from -4 to -8 which would be 4 because |-4 - -8| = |-4 + 8| = 4.

Final answer: 4

Hope this helps.
Reptile [31]3 years ago
5 0
To find the distance between two given points, use the distance formula. The distance formula is √((x₁ - x₂)² + (y₁ - y₂)²), where x₁, x₂, y₁, and y₂ are the x- and y-points of the given coordinates. Let's plug in our values and solve.

Coordinates: (-4, 3) and (-8, 3)

Distance formula:
√((x₁ - x₂)² + (y₁ - y₂)²)

Plug in the points:
√((-4 - (-8)² + (3 - 3)²)
√((-4 + 8)² + (3 - 3)²)

Combine the constants:
√(4² + 0²)

Square 4 and 0:
√(16 + 0)
√(16)

Take the square root of 16:
4

Answer:
The distance between the pair of points is 4 units.
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I need help with this
evablogger [386]

Answer:

A) (-8, -16)

B) (0, 48)

C) (-4, 0), (-12, 0)

Step-by-step explanation:

A) the vertex is the minimum y value.

extremes of a function we get by using the first derivation and solving it for y' = 0.

y = x² + 16x + 48

y' = 2x + 16 = 0

2x = -16

x = -8

so, the vertex is at x=-8.

the y value is (-8)² + 16(-8) + 48 = 64 - 128 + 48 = -16

B) is totally simple. it is f(0) or x=0. so, y is 48.

C) is the solution of the equation for y = 0.

the solution for such a quadratic equation is

x = (-b ± sqrt(b² - 4ac)) / (2a)

in our case here

a=1

b=16

c=48

x = (-16 ± sqrt(16² - 4×48)) / 2 = (-16 ± sqrt(256-192)) / 2 =

= (-16 ± sqrt(64)) / 2 = (-16 ± 8) / 2 = (-8 ± 4)

x1 = -8 + 4 = -4

x2 = -8 - 4 = -12

so the x- intercepts are (-4, 0), (-12, 0)

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