Answer:
7.5 Quarts
Step-by-step explanation:
D'Naisa mixed the following:
- 1 gallon of orange paint
- 2 quarts of yellow paint
- 3 pints of red paint.
We are to determine in total, the number of quarts of paint that she mixed. this is done by converting each of the volume to quart.
<u>1 gallon of orange paint</u>
- 1 gallon = 4 Quarts
- Orange Paint=4 Quarts
<u>3 pints of red paint.</u>
- 1 pint =0.5 quart
- 3 Pints =3 X 0.5 Quart
- =1.5 Quart of red paint
Therefore,
Total Volume of Paint Mixed in quart= Volume of Orange+Yellow+Red
=4+2+1.5
=7.5 Quarts
Step-by-step explanation:
y = kx, where k is the constant of proportionality. (1)
Therefore y = x and line B depicts that.
To estimate the distance between the tip of his fishingrod which is above the water and the hook which is below the water, you will need to estimate the absolute values of both distances.
|53 3/4| + |12 2/3|54 + 1367 ft
Trents estimate is not reasonable because you would around both of these values up to the next whole number making it greater than 65.
Alright. So We Need To Take A Look At The Answer Choices. The Sum Of Two Rational Numbers Is Always Rational. This Is True. You Cant Add Bad With Bad And Get Good. So You Will Always Get Rational Numbers, So It Is Not A.
Lets Look At B. <span>The product of a nonzero rational number and an irrational number is always irrational. This is True. Pi Times Any Number Is Irrational. If You Have A Repeating Decimal,You Can't Change It To A Whole Number.
Lets Look At C. </span><span>The product of two rational numbers is always rational. This Is True. Any Rational Numbers Multiplied Will Always Be Rational. 3.5 * 4 = 14. this Is Still Rational, So Not C.
Lets Look At D. </span><span>The sum of two irrational numbers is always rational.This Is Not True. If You Do: Pi + Pi, This Will Not Be Rational. So, It Is D.
So, Having Looked At All The Choices, The Answer Is D.
</span>
First of all, we need all logarithms to have the same base. So, we use the formula

To change the second term as follows:

Finally, using the property

we have

So, the equation becomes

We can now use the formula

to write the equation as

Now consider both sides as exponents of 2:

This equation has no "nice" solution, so I guess the problem is as simplifies as it can be