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ahrayia [7]
3 years ago
13

A baby gains 11 pounds in its first year of life. The baby gained 4 1/4 pounds during the first four months and 3 1/2 pounds in

its second four months. How much did the baby gain in the last four months?
Mathematics
2 answers:
Sati [7]3 years ago
5 0
The answer is 3.25 pounds.
The total of the 8 months adds up to 7.75 pounds.
When subtracted to 11 pounds, you get 3.25 pounds.
Let me know if you need help with anything else :)
FromTheMoon [43]3 years ago
4 0
Yhe baby gained 3 1/4 pounds
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3 years ago
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Element X decays radioactively with a half life of 12 minutes. If there are 160
Salsk061 [2.6K]

Answer:

It would take 75.8 minutes for the element to decay to 2 grams.

Step-by-step explanation:

The number of grams of element x, after t minutes, is given by the following equation:

X(t) = X(0)(1-r)^{t}

In which X(0) is the initial amount and r is the decay rate.

There are 160 grams of Element X

This means that X(0) = 160.

So

X(t) = X(0)(1-r)^{t}

X(t) = 160(1-r)^{t}

Half life of 12 minutes.

This means that X(12) = 0.5*X(0) = 0.5*160 = 80. So

X(t) = 160(1-r)^{t}

80 = 160(1-r)^{12}

(1 - r)^{12} = 0.5

\sqrt[12]{(1 - r)^{12}} = \sqrt[12]{0.5}

1 - r = 0.9438

So

X(t) = 160(1-r)^{t}

X(t) = 160(0.9438)^{t}

How long would it take for the element to decay to 2 grams?

This is t for which X(t) = 2. So

X(t) = 160(0.9438)^{t}

2 = 160(0.9438)^{t}

(0.9438)^{t} = \frac{2}{160}

\log{(0.9438)^{t}} = \log{\frac{2}{160}}

t\log{0.9438} = \log{\frac{2}{160}}

t = \frac{\log{\frac{2}{160}}}{\log{0.9438}}

t = 75.8

It would take 75.8 minutes for the element to decay to 2 grams.

6 0
3 years ago
Please help it’s a math test! My grade depends on it!!
nignag [31]

Answer:

Number 2 is 63.  He collects 63 stickers in total after 9 days

Step-by-step explanation:

Based on the table, Ashley collects 7 stickers a day.  If you want to know how many stickers she collects after 9 days, you need to do 7 x 9, which equals 63.

Hope that helped!  Good luck! :D

6 0
3 years ago
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Find the equation of the line with slope m=−34 that contains the point (8,−9).
asambeis [7]
Y=mx+b

subbing in m=-34
y=-34x+b

subbing in x=8 and y=-9
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solve for b:
b= 263

therefore, the equation of the line is
y=-34x+263
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3 years ago
HELP PLZ! WILL GIVE BRAINLIEST.
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Answer:

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Step-by-step explanation:

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