The numeric value of the expression d² + 3a + 6 + a when a = 2 and d = 5 is of 39.
<h3>How to find the numeric value of an expression?</h3>
The numeric value of a function is found replacing each instance of a variable by the value of the input for which we want to find the numeric value.
For this problem, the expression is given by:
d² + 3a + 6 + a
We want to find the numeric value when a = 2 and d = 5, hence:
5² + 3(2) + 6 + 2 = 25 + 6 + 6 + 2 = 39.
More can be learned about the numeric values of a function at brainly.com/question/14556096
#SPJ1
Tan30=9/x so it will be 9((3)^1/2)
Given:
The function is
Consider the given domain of g is {-2,0,2}.
To find:
The solution set if the domain of g for the given domain.
Solution:
Domain is the set of input values and range is the set of output value.
We have,
Domain of g is {-2,0,2}.
For x=-2,
For x=0,
For x=2,
Now, the solution set of the given domain of g is
Therefore, the solution set is {18,12,6}.
Number of bacteria = 64•(1.5^(t/4))
So after t=100 hours,
64•(1.5^25) = 1,616,075 or 1.616x10^6
Answer:
the equation is 2(l+w) so we do 2(93+w)=344 getting the answer of 79
Step-by-step explanation:
i think im 100 percent correct i took the test on flvs if I'm wrong just let me know
