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Darya [45]
4 years ago
6

A teacher has 3 hours to grade all the papers submitted by the 35 students in her class. She gets through the first 5 papers in

30 minutes. How much faster does she have to work to grade the remaining papers in the allotted time? Will it be wrong if I say '' she has to be 1.2 times faster instead of 20% faster?''
Mathematics
1 answer:
RideAnS [48]4 years ago
8 0

Let us calculate the teacher's initial speed. It can be calculated as thus:

She does 5 papers in 30 minutes. Thus means her speed is 6 minutes per paper (Because \frac{30}{5}=6 minutes per paper).

Now, if the teacher has to complete the remaining 30 papers in the remaining 150 minutes (2 hours 30 minutes=120+30=150 minutes), she will have to go through one paper in \frac{150}{30}=5 minutes. Thus, her speed now will have to be 5 minutes per paper.

Now, we know that 1.2 times 5=6. Therefore, it will not be wrong to say that '' she has to be 1.2 times faster instead of 20% faster" because both mean the same.

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Find the vertices and foci of the hyperbola with equation quantity x plus 5 squared divided by 36 minus the quantity of y plus 1
Sphinxa [80]

Answer:

Vertices: (1,-1), (-11, -1); Foci: (-15, -1), (5, -1)

Step-by-step explanation:

Center at (-5,-1) because of the plus 5 added to the x and the plus 1 added to the y.

a(squared)=36 which means a=6 and a=distance from center to vertices so add and subtract 6 from the x coordinate since this is a horizontal hyperbola, which is (1,-1), (-11,-1). From there you dont need to find the focus since there is only one option for this;

Vertices: (1,-1), (-11, -1); Foci: (-15, -1), (5, -1)

8 0
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Please help. Thank you​
love history [14]

Answer:

The length of side x is x = \sqrt{6}

Step-by-step explanation:

Pythagorean Theorem:

In a right triangle, with sides a and b, and hypothenuse h, we have that:

a^2 + b^2 = h^2

In this question:

The vertical line on the sides means that both are equal, that is, measuring x, so a = b = x.

Hypothenuse is the square root of 12. So h = \sqrt{12}

x^2 + x^2 = (\sqrt{12})^2

2x^2 = 12

x^2 = \frac{12}{2}

x^2 = 6

x = \sqrt{6}

The length of side x is x = \sqrt{6}

8 0
2 years ago
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