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3 years ago

Identify the type of chemical bond in a molecule reactant

2 answers:

8 0

Draw the electron-dot (Lewis) structure of O2. You will see that there is a double bond, thus making the chemical bond a covalent bond since they have to share a pair of electrons in order to complete their octet.

Vladimir79 [104]3 years ago

3 0

Answer : The type of chemical bond form in $O_2$ molecule is covalent bond.

Explanation:

Ionic bond : It is defined as the bond that is formed by complete transfer of electrons from one atom to another atom.

That means, the atom which looses the electron is known as electropositive atom and the atom which gains the electron is known as electronegative atom.

The ionic bond is usually formed between a metal and a non-metal.

Covalent bond : It is defined as the bond which is formed when sharing of electrons takes place between the atoms.

This is usually formed between two non-metals.

The given reaction is:

$O_2+Energy\rightarrow O(g)+O(g)$

In this reaction, the reactant is $O_2$ molecule.

In $O_2$ molecule, oxygen is non-metal. So, two oxygen atom will form a covalent bond by the sharing of four electrons.

Hence, the type of chemical bond form in $O_2$ molecule is covalent bond.

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Mr. Romeo wants to make a solution of NaOH. He measures out 85.66 grams and puts it into 7 liters.

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3 years ago

What is the easiest way to explain molecular compounds and covalent bonds also adding information about valance electrons?

wlad13 [49]

Answer:

Molecular compounds consist of two or more nonmetals. The nonmetals that make up a molecular compound are held together by covalent/molecular bonds. Covalent bonds is known as the "sharing" of valence electrons between two or more chemical species. Valence electrons are shared so that the atoms of the compound can become stable, much like how ionic bonds transfer valence electrons between atoms to achieve stability.

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3 years ago

Which of the following properties can be

Aleonysh [2.5K]

Answer:

Ability to conduct electricity

Melting point

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3 years ago

A cup of hot water cannot melt a large block of ice. However, the same block melts when dropped into a lake. This is because

masya89 [10]

Explanation:

When a large block of ice is placed in a hot cup of water then some of the ice will melt into the cup. As a result, when ice melts then after sometime temperature of cup will become equal to the temperature of ice.

Therefore, ice won't melt further as surface area of cup is small so, only some of the ice will melt into it.

Whereas when same block melts when dropped into a lake it completely melts because lake has large surface area and hence, ice will melt into it easily. This is also because there is different in temperature of both ice and lake.

So, ice will melt into it as temperature of ice will be less than the temperature of lake.

6 0

4 years ago

Read 2 more answers

Which statement below correctly describes the relationship between Q and K for both reactions? Are these reactions spontaneous a

nikklg [1K]

Answer:

Q < K for both reactions. Both are spontaneous at those concentrations of substrate and product.

Explanation:

Hello,

In this case, the undergoing chemical reactions with their proper Gibbs free energy of reaction are:

$A->B;\Delta _rG^o=-13 kJ/mol$

$C ->D ;\Delta _rG^o=3.5 kJ/mol$

The cellular concentrations are as follows: [A] = 0.050 mM, [B] = 4.0 mM, [C] = 0.060 mM and [D] = 0.010 mM.

For each case, the reaction quotient is:

$Q_1=\frac{4.0mM}{0.050mM}=80\\ Q_2=\frac{0.010mM}{0.060mM}=0.167$

A typical temperature at a cell is about 30°C, in such a way, the equilibrium constants are:

$K_1=exp(-\frac{-13000J/mol}{8.314J/mol*K*303.15K} )=173.8\\K_2=exp(-\frac{3500J/mol}{8.314J/mol*K*303.15K} )=0.249$

Therefore, Q < K for both reactions. Both are spontaneous at those concentrations of substrate and product.

Best regards.

6 0

3 years ago