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VladimirAG [237]
1 year ago
6

unknown element x has a mass number of 88 and contains 50 neutrons in the atom. element x is strontium

Chemistry
1 answer:
AnnyKZ [126]1 year ago
5 0

Strontium element has a mass number of 88 and contains 50 neutrons in the atom.

Given that;

Mass number of element X = 88

Number of Neutrons in element X = 50

we know the concept that Mass number is represent as total number of Neutrons and proton present in Nucleus

So, Mass number of element X = Number of Neutrons in element X + Number of Protons in element X

Thus, 88 = 50 + Number of Protons in element X

Number of Protons in element X = 38

As, Number of proton = Atomic number

So, Atomic number of element X = 38

Hence Unknown Element X is Strontium

To know more about Strontium element visit here ; brainly.com/question/19298437?referrer=searchResults

#SPJ4

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How many grams of NaCI are present in 11.00 moles
Amiraneli [1.4K]

Answer: 642.93 g of NaCl

Explanation:

11.00 mol NaCl  x  __58.448 g__  =  642.928 g of NaCl

                                 1 mol NaCl

I would round to 642.93 g of NaCl, but round to however many significant figures asked for.

My chemistry teacher made this map (image attached) to teach us how to do conversions. Just follow the map. I think it's pretty straight forward. I hope this helps.

7 0
3 years ago
In which reaction does the oxidation number of hydrogen change? In which reaction does the oxidation number of hydrogen change?
dedylja [7]

<u>Answer:</u> The correct answer is 2Na(s)+2H_2O(l)\rightarrow 2NaOH(aq.)+H_2(g)

<u>Explanation:</u>

Oxidation number is defined as the number which is given to an atom when it looses or gains electron. When an atom looses electron, it attains a positive oxidation state. When an atom gains electron, it attains a negative oxidation state.

Oxidation state of the atoms in their elemental state is considered as 0. Hydrogen is present as gaseous state.

For the given chemical reactions:

  • <u>Reaction 1:</u>  2HClO_4(aq.)+CaCO_3(s)\rightarrow Ca(ClO_4)_2(aq.)+H_2O(l)+CO_2 (g)

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: +1

Thus, the oxidation state of hydrogen is not changing.

  • <u>Reaction 2:</u>  CaO(s)+H_2O(l)\rightarrow Ca(OH)_2(s)

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: +1

Thus, the oxidation state of hydrogen is not changing.

  • <u>Reaction 3:</u>  HCl(aq.)+NaOH(aq.)\rightarrow NaCl(aq.)+H_2O(l)

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: +1

Thus, the oxidation state of hydrogen is not changing.

  • <u>Reaction 4:</u>  2Na(s)+2H_2O(l)\rightarrow 2NaOH(aq.)+H_2(g)

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: 0

Thus, the oxidation state of hydrogen is changing.

  • <u>Reaction 5:</u>  SO_2(g)+H_2O(l)\rightarrow H_2SO_3(aq.)

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: +1

Thus, the oxidation state of hydrogen is not changing.

Hence, the correct answer is 2Na(s)+2H_2O(l)\rightarrow 2NaOH(aq.)+H_2(g)

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Answer:

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