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blondinia [14]
3 years ago
12

On the number line, a bug A is moving in the positive direction from the point 0, and a bug Bis moving in the negative direction

from the point 0. The speeds of both bugs are constant. Both leave 0 at the same time, and three seconds later A has reached 18 and B has reached –15. b When will A and B be 220 units apart?
Mathematics
1 answer:
AleksAgata [21]3 years ago
8 0

Answer:

20 seconds

Step-by-step explanation:

A is moving at the speed of 6t and B is moving at the speed of 5t. 6t +5t = 11t, and 220 divided by 11 = 20.

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Frank is using a cookie recipe that calls for 2 ¼ cups of flour. The recipe yields 20 cookies. How much flour would be needed to
larisa86 [58]

Hey there! I'm happy to help!

How many times does 20 go into 48?

48/20=2.4

So, we multiply our amount of flour for 20 cookies by 2.4.

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3 years ago
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Anuta_ua [19.1K]

Answer:

<h3><u>Let's</u><u> </u><u>understand the concept</u><u>:</u><u>-</u></h3>

Here angle B is 90°

So \triangle ABC and \triangle ABD Are right angled triangle

So we use Pythagoras thereon for solution

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>
  • First in triangle ABC

perpendicular=p=8cm

Hypontenuse =h =10cm

  • We need to find base=b

According to Pythagoras thereon

{\boxed{\sf b^2=h^2-p^2}}

  • Substitutethe values

\longrightarrow\sf b^2=10^2-p^2

\longrightarrow\sf b={\sqrt {10^2-8^2}}

\longrightarrow\sf b={\sqrt{100-64}}

\longrightarrow\bf b={\sqrt {36}}

\longrightarrow\sf b=6

\therefore\overline{BC}=6cm

  • BD=BC+CD

\longrightarrowBD=9+6

\longrightarrowBD=15cm

  • Now in \triangle ABD

Perpendicular=p=8cm

Base =b=15cm

  • We need to find Hypontenuse =AD(x)

According to Pythagoras thereon

{\boxed {\sf h^2=p^2+b^2}}

  • Substitute the values

\longrightarrow\sf h^2=8^2+15^2

\longrightarrow\sf h={\sqrt {8^2+15^2}}

\longrightarrow\sf h={\sqrt {64+225}}

\longrightarrow\sf h={\sqrt {289}}

\longrightarrow\sf h=17cm

\therefore{\underline{\boxed{\bf x=17cm}}}

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