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faust18 [17]
3 years ago
15

HELP!!!!!!!

Mathematics
2 answers:
igomit [66]3 years ago
7 0

Substituting the data points into the model:

f(x)= -x2 + 2x -3

f(-2)=-11

f(0)=-3

f(1)=-2

f(3)=-6

f(5)=-18

So A is the right ans.


djverab [1.8K]3 years ago
3 0
See attached plot of the data, the model best-fit them is: <span>f(x) = – x2+ 2x - 3 </span>

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What is the product of −4 1/2 and 2 1/2?
xz_007 [3.2K]
<h3>Solution:</h3>

- 4 \frac{1}{2}  \times 2 \frac{1}{2}  \\  =  \frac{ - 9}{2}  \times  \frac{5}{2}  \\  =  \frac{ - 45}{4}  \\  =  - 11 \frac{1}{4}

<h3>Hope it helps</h3>

ray4918 here to help

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Answer:

Median: 85

Mode: 85

Range: 20

Mean: 86

Step-by-step explanation:

7 0
3 years ago
Write the linear inequality in slop-intercept form. 4x - 6y ≥ 16
Pachacha [2.7K]
2/3x -8/3 >= y is the answer
3 0
3 years ago
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Question 15 of 16
Westkost [7]

The same input is being mapped into two outputs, so this is not a function.

<h3>Does the table represent a function?</h3>

A function is a relation that maps elements from the domain into elements from the range. Such that each element of the domain can be mapped into only one element of the range.

Here we have the table:

x    y

4   2

3   3

4   5

5   6

7   7

As you can see, the input x = 4 appears two times, first it is mapped into y = 2, and then it is mapped into y = 5.

Then this table does not represent a function.

If you want to learn more about functions:

brainly.com/question/2328150

#SPJ1

7 0
2 years ago
Used use euler's method with step size 0.1 to estimate y(0.5), where y(x) is the solution of the initial-value problem y ' = y +
brilliants [131]
We want to solve the Initial Value Problem y' = y + 4xy, with y(0) = 1.

To use Euler's method, define
y(i+1) = y(i) + hy'(i),  for i=0,1,2, ..., 
where
h = 0.1, the step size.,
x(i) = i*h

1st step.
y(0) = 1 (given) and x(0) = 0.
y(1) ≡ y(0.1) = y(0) + h*[4*x(0)*y(0)] = 1 

2nd step.
x(1) = 0.1
y(2) ≡ y(0.2) = y(1) + h*[4*x(1)*y(1)] = 1 + 0.1*(4*0.1*1) = 1.04

3rd step.
x(2) = 0.2
y(3) ≡ y(0.3) = y(2) + h*[4*x(2)*y(2)] = 1.04 + 0.1*(4*0.2*1.04) = 1.1232

4th step.
x(3) = 0.3
y(4) ≡ y(0.4) = y(3) + h*[4*x(3)*y(3)] = 1.1232 + 0.1*(4*0.3*1.1232) = 1.258

5th step.
x(4) = 0.4
y(5) ≡ y(0.5) = y(4) + h*[4*x(4)*y(4)] = 1.258 + 0.1*(4*0.4*1.258) = 1.4593

Answer:  y(0.5) = 1.4593
4 0
3 years ago
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