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Taya2010 [7]
4 years ago
12

A lot of 100 semiconductor chips contains 15 that are defective. three chips are selected at random from the lot without replace

ment. what is the probability that the third chip is defective?
Mathematics
1 answer:
Alex787 [66]4 years ago
5 0
D=event that chip selected is defective
d=event that chip selected is NOT defective

Four possible scenarios for the first two selections:
P(DDD)=15/100*14/99*13/98=13/4620
P(DdD)=15/100*85/99*14/98=17/924
P(dDD)=85/100*15/99*14/99=17/924
P(ddD)=85/100*84/99*15/98=17/154

Probability of third selection being defective is the sum of all cases,
P(XXD)=P(DDD)+P(DdD)+P(dDD)+P(ddD)
=3/20


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A desk is 39 inches wide. What is the width in yards
Stolb23 [73]

Answer:

1.0833 yd

Step-by-step explanation:

Inches    Yards

37"         1.0278 yd

38"         1.0556 yd

39"         1.0833 yd

40"         1.1111 yd

Have a great day! :D

4 0
3 years ago
What is the solution of the system? Use the elimination method. 2x+y=206x−5y=12 Enter your answer in the boxes.
astraxan [27]

Answer:

The answer to your question is:   x = 7; y = 6

Step-by-step explanation:

                                             2x+y=20             ( 1 )  Multiply by 5

                                             6x−5y=12            ( 2 )

                               5 (2x+y=20)    = 10x + 5y = 100

                                          10x + 5y = 100

                                            6x − 5y =   12             Eliminate y

                                          16 x        = 112

                                           x = 112 / 16

                                           x = 7

                                 2(7) + y = 20                 Substitution

                                 14 + y = 20

                                 y = 20 - 14

                                 y = 6

7 0
3 years ago
Presents of equal size are in a boxes each with dimensions of 10 inches length, 4 inches width, and 2 inches height. How many pr
Maurinko [17]

Answer:

You can make 7.5 gifts presents (or just 7)

Step-by-step explanation:

First I calculated the area of 1 box, which is 80 inches squared. Then I just divided the 600 square inches with the 80 inches. 600/80= 7.5. Therefore, you can make 7 presents (since you cannot wrap half of a present (0.5))

Hope this helps !

4 0
2 years ago
I need help on this question plz
Gnom [1K]

That's unbiased.

That's unbiased.

5 0
3 years ago
Read 2 more answers
If 2 pieces of pizza and 3 candy bars cost $8 and 6 pieces of pizza and 5 candy bars cost $20, what is the cost of one piece of
Minchanka [31]

Answer:

One piece of pizza = $2.5

One candy bar = $1

Step-by-step explanation:

Call 1 pizza a, 1 candy bar b. We have:

2a + 3b = $8

=> 3(2a+3b) = 3. $8

= 6a + 9b = $24

and

6a + 5b = $20

=> (6a + 9b) - (6a + 5b) = 9b - 5b = 4b = $24 - $20 = $4

=> b = $1

=> 2a + $3 = $8

=> 2a = $5

=> a = $2.5

So one piece of pizza = $2.5, one candy bar = $1

4 0
2 years ago
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