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Simora [160]
3 years ago
6

What is the y=Mx+b of this equation

Mathematics
1 answer:
Monica [59]3 years ago
4 0

Answer:

y =  - 6x - 8

Step-by-step explanation:

The y-intercept is where the line itersects the y-axis, which is the dark vertical line. This is -8 represented as the constant in the equation.

To find the slope, find the rise over run. Every time the line goes over 1 it goes down 6, so the slope would be -6.

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What is the value of the square root of 25 + the square root of 16?​
kozerog [31]

Answer:9

Step-by-step explanation: square root of 25 is 5 and of 16 the square root is 4 add both of them together and you get 9

6 0
3 years ago
Read 2 more answers
You deposit $50 in your savings account. One week later, you withdraw $20. Write each amount as an integer
Sloan [31]
Deposit mean add 50, then withdraw means taking out 20, you do subtraction: $50-$20=$30

4 0
3 years ago
HELP ME PLZ!!!!!!!!!!
nevsk [136]


C. No, this is not a valid inference because she asked only 35 families

4 0
3 years ago
Please help it’s so difficult
Sergeu [11.5K]

Answer:

y = x/2 +4

Step-by-step explanation:

new slope = -1/-2 = 1/2

x1 = -4, y1= 2

y-y1 = m(x-x1)

y - 2 = 1/2 {x- (-4)}

y-2 = 1/2 (x+4)

y-2 = x/2 + 2

y = x/2 +2+2

y = x/2 +4

3 0
3 years ago
According to the Center for Disease Control and Prevention (CDC), up to 20% of Americans contract the influenza virus each year,
12345 [234]

Answer:

(1) a. 0.0009

(2) d. 0.640

(3)

  • a. P(A and B) = 0.06.
  • b. P(A or B) = 0.70.

(4)Not disjoint

(5) a. nearly 0.

(6)b. 0.919

Step-by-Step Explanation:

(1)Probability of a baby being born with a birth defect =3%=0.03

The probability that both babies have birth defects=0.03 X 0.03= 0.0009.

(2)The probability of contracting the influenza virus each year = 20%=0.2

Therefore, the probability of not contracting the influenza virus =1-0.2=0.8

The probability that neither baby catches the flu in a given year:

=0.8 X  0.8

=0.64

(3)

P(A)=0.1

P(B)=0.6

P(A or B)=P(A)+P(B)=0.1 + 0.6 =0.7

P(A and B)=P(A)XP(B)=0.1 X 0.6 =0.06

(4)

P(A)=0.2

P(B)=0.9

Event A and B cannot be disjoint.

(5)

The probability of an American woman aged 20 to 24 having Chlamydia infection  =\dfrac{2791.5}{100000}

The probability that three randomly selected women in this age group have the infection

=\dfrac{2791.5}{100000} \times \dfrac{2791.5}{100000} \times \dfrac{2791.5}{100000} \\\\=0.00002175\\\approx 0

(6)The probability of an American woman aged 20 to 24 not having Chlamydia infection  =1-\dfrac{2791.5}{100000}

The probability that three randomly selected women in this age group do not have the infection

=\left(1-\dfrac{2791.5}{100000}\right)^3\\\\=0.9186\\\approx 0.919

7 0
4 years ago
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