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djverab [1.8K]
3 years ago
15

What are two ratios that are equivalent to 27:9

Mathematics
2 answers:
mixas84 [53]3 years ago
5 0

The given ratio is 27:9

we are supposed ratios equivalent to the given ratio.

The equivalent ratios can be found in two ways.

Either multiplying the numerator and denominator by a number or by dividing the numerator and denominator by a number.

Lets re-write the given ratio as below

27:9=\frac{27}{9}\\ \\ \text{Divide numerator and denominator by 3 we get}\\  \\ \frac{27}{9} = \frac{9}{3} \Rightarrow \text{Ratio is } 9:3\\ \\ \text{Now again divide numerator and denominator by 3 we get}\\ \\  \frac{9}{3} =\frac{3}{1} \Rightarrow \text{Ratio is } 3:1\\ \\\\\text{Hence the two equivalent ratios are }9:3  \ and \ 3:1.

skad [1K]3 years ago
3 0
For this case we have the following relationship:
 27:9
 To find two equivalent relationships, what we must do is divide both numbers by a number that is multiple of both.
 We then have to divide by three:
 9:3
 Then, dividing again between three we have:
 3:1
 Answer:
 two ratios that are equivalent to 27:9 are:
 Ratio 1:
 9:3
 Ratio 2:
 3:1
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Answer:

D. 16 inches by 8 inches

Step-by-step explanation:

We have been given an image of two rectangles and we are asked to find the dimensions of the enlarged rectangle.

Since we have been given that the original rectangle is enlarged b a scale factor of 4, so to find the dimensions of enlarged rectangle we will multiply the dimensions of original rectangle by 4.

\text{Length of enlarged rectangle}=4\times 4\text{ inch}

\text{Length of enlarged rectangle}=16\text{ inch}

\text{Width of enlarged rectangle}=4\times 2\text{ inch}

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Therefore, the dimensions of enlarged rectangle are 16 inches by 8 inches and option D is the correct choice.

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 Your answer would be x = 3.0645

CHECK
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Hope this helps!

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A distribution of values is normal with a mean of 60 and a standard deviation of 16. From this distribution, you are drawing sam
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Answer:

The interval containing the middle-most 76% of sample means is between 56.24 and 63.76.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

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For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

A distribution of values is normal with a mean of 60 and a standard deviation of 16.

This means that \mu = 60, \sigma = 16

Samples of size 25:

This means that n = 25, s = \frac{16}{\sqrt{25}} = 3.2

Find the interval containing the middle-most 76% of sample means.

Between the 50 - (76/2) = 12th percentile and the 50 + (76/2) = 88th percentile.

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X when Z has a p-value of 0.12, so X when Z = -1.175.

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X - 60 = -1.175*3.2

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X - 60 = 1.175*3.2

X = 63.76

The interval containing the middle-most 76% of sample means is between 56.24 and 63.76.

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